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2 years ago

13

Find the measure of each angle indicated.

1 answer:

Alexandra [31]2 years ago

5 0

50 because 80+50+x=180 (inside triangle) x=130 180-130= 50 (angle outside triangle)

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Please show all work!! this is algebra.

Mnenie [13.5K]

Franco:
3x+2y=19
Caryl:
2x+4y=24

now use elimination

-2(3x+2y=19)
1(2x+4y=24)
=
-6x-4y=-38
2x+4y=24
add them together
which equals -4x=-14
divide both sides by -4
-4x/-4=-14/-4
x=7/2

we found x, so we subsitute it into the the original equation

3x+2y=19
3(7/2)2y=19
2y+21/2=19
-21/2 -21/2
2y=17/2
divide by 2 on both sides
2y/2= 17/2/2
y=17/4

so x= 7/2 and y= 17/4

8 0

2 years ago

Multiply and simplify (4x-2)(3x^2-2x+1) Write answer in standard form

hjlf

Answer:

<h3>12<em>x</em>^3 - 14<em>x</em>^2 + 8<em>x</em> - 2</h3>

7 0

2 years ago

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guyssss please help me with this maths problem it's from coordinates I hope you will help me I literally need this one pls will

aliina [53]

Answer:

find the perpendicular of the angle of pole

7 0

3 years ago

What is the 38th term of 459,450,441,..

galina1969 [7]

Answer:

The 38th term of 459,450,441,.. will be:

$a_{13}=351$

Step-by-step explanation:

Given the sequence

$459,450,441,..$

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

computing the differences of all the adjacent terms

$450-459=-9,\:\quad \:441-450=-9$

so

$d=-9$

The first element of the sequence is

$a_1=459$

so the nth term will be

$a_n=-9\left(n-1\right)+459$

$a_n=-9n+468$

Putting n=38 to find the 38th term

$a_n=-9n+468$

$a_{13}=-9\left(13\right)+468$

$a_{13}=-117+468$

$a_{13}=351$

Therefore, the 38th term of 459,450,441,.. will be:

$a_{13}=351$

3 0

3 years ago

Please explain how u get the answer thanks! <br> (Last question)

love history [14]

Answer:

money made by michael = 15*3 +6*5 = 45+30= $75

Step-by-step explanation:

3 0

3 years ago

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