Answer:
34.8 mL
Explanation:
First we <u>convert 5.48 g of CuNO₃ into moles</u>, using its<em> molar mass</em>:
- 5.48 g CuNO₃ ÷ 187.56 g/mol = 0.0292 mol
Now we can <u>calculate the volume of the solution</u>, using the <em>definition of molarity</em>:
- Molarity = moles / liters
- 0.840 M = 0.0292 mol / liters
Finally we <u>convert L into mL</u>:
- 0.0348 L * 1000 = 34.8 mL
Answer:
1.98 g
Explanation:
The balanced reaction would be:
2CO + O2 = 2CO2
We assume that the gases are ideal gas so that we use the relation that 1 mol of an ideal gas is equal to 22.4 L of the gas at STP. From that relation, we get the number of moles and we can convert it to other units. We do as follows:
1.0 L CO ( 1 mol / 22.4 L ) ( 2 mol CO2 / 2mol CO ) = 0.045 mol CO2 produced
0.045 mol CO2 ( 22.4 L / 1 mol ) = 1 L of CO2
0.045 mol CO2 ( 44.01 g / 1 mol ) = 1.98 g of CO2
Answer:
1077.3 molecular in 1.05*1026 molecules
Actually, we can answer the problem even without the first statement. All we have to do is write the reaction for the production of sulfur trioxide.
2 S + 3 O₂ → 2 SO₃
The stoichiometric calculations is as follows:
6 g S * 1 mol/32.06 g S = 0.187 mol S
Moles O₂ needed = 0.187 mol S * 3 mol O₂/2 mol S = 0.2805 mol O₂
Since the molar mas of O₂ is 32 g/mol,
Mass of O₂ needed = 0.2805 mol O₂ * 32 g/mol = 8.976 g O₂
Answer:
answer = 22.5m
Explanation:
using
s= (0²-21²)/2(-9.8)
s= -441/19.6
s= 22.5m
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