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dsp73
3 years ago
10

If you have a 1234 gram sample of C4H7NO4, how many gams of Carbon would be present?

Chemistry
1 answer:
Tpy6a [65]3 years ago
8 0

Answer: 445.4 grams of carbon would be present.

Explanation:

According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{1234g}{133g/mol}=9.28moles

As 1 mole of C_4H_7NO_4 gives = 4 moles of carbon

Thus 9.28 moles of C_4H_7NO_4 gives = \frac{4}{1}\times 9.28=37.1 moles of carbon

Mass of carbon = moles\times {\text {Molar mass}}=37.1moles\times 12g/mol=445.4g

Thus there are 445.4 grams of carbon would be present.

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