Question

If you have a 1234 gram sample of C4H7NO4, how many gams of Carbon would be present?

Answer 1

Answer: 445.4 grams of carbon would be present.

Explanation:

According to avogadro's law, 1 mole of every substance contains avogadro's number $6.023\times 10^{23}$ of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{1234g}{133g/mol}=9.28moles$

As 1 mole of $C_4H_7NO_4$ gives = 4 moles of carbon

Thus 9.28 moles of $C_4H_7NO_4$ gives = $\frac{4}{1}\times 9.28=37.1$ moles of carbon

Mass of carbon = $moles\times {\text {Molar mass}}=37.1moles\times 12g/mol=445.4g$

Thus there are 445.4 grams of carbon would be present.