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ira [324]
3 years ago
15

-1/8(x-4)=-4 how do i show my work

Mathematics
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer: the answer is x=36

Step-by-step explanation:

Simplify  \frac{1}{8}(x-4)

8

1

​

(x−4)  to  \frac{x-4}{8}

8

x−4

​

.

-\frac{x-4}{8}=-4

−

8

x−4

​

=−4

2 Multiply both sides by 88.

-x+4=-4\times 8

−x+4=−4×8

3 Simplify  4\times 84×8  to  3232.

-x+4=-32

−x+4=−32

4 Regroup terms.

4-x=-32

4−x=−32

5 Subtract 44 from both sides.

-x=-32-4

−x=−32−4

6 Simplify  -32-4−32−4  to  -36−36.

-x=-36

−x=−36

7 Multiply both sides by -1−1.

x=36

x=36

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Answer: I think the asnwer is c

Step-by-step explanation:

I suggest this because when your looking at the two different triangles your looking at the sides and the whole shape

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3 years ago
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I need help on this one
umka2103 [35]
You seem to have gotten m∠2. Remember that ∠1 and ∠2 are alternate interior angles, meaning they're both equal. Since they gave you m∠1 as being 26°, you now know the measure of ∠2.

As for m∠3 and m∠4, If you look at ∠3 you'll see that it is complementary to ∠1 (They both add up to 90°), so if you subtract m∠1 from 90° you'll have found m∠3. You find m∠4 the same way.

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6 0
3 years ago
A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si
Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

Area = 128

Let the dimension of the paper be x and y;

Such that:

Length = x

Width = y

So:

Area = x * y

Substitute 128 for Area

128 = x * y

Make x the subject

x = \frac{128}{y}

When 1 inch margin is at top and bottom

The length becomes:

Length = x + 1 + 1

Length = x + 2

When 2 inch margin is at both sides

The width becomes:

Width = y + 2 + 2

Width = y + 4

The New Area (A) is then calculated as:

A = (x + 2) * (y + 4)

Substitute \frac{128}{y} for x

A = (\frac{128}{y} + 2) * (y + 4)

Open Brackets

A = 128 + \frac{512}{y} + 2y + 8

Collect Like Terms

A = \frac{512}{y} + 2y + 8+128

A = \frac{512}{y} + 2y + 136

A= 512y^{-1} + 2y + 136

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

A' = -512y^{-2} + 2

Set

A' = 0

This gives:

0 = -512y^{-2} + 2

Collect Like Terms

512y^{-2} = 2

Multiply through by y^2

y^2 * 512y^{-2} = 2 * y^2

512 = 2y^2

Divide through by 2

256=y^2

Take square roots of both sides

\sqrt{256=y^2

16=y

y = 16

Recall that:

x = \frac{128}{y}

x = \frac{128}{16}

x = 8

Recall that the new dimensions are:

Length = x + 2

Width = y + 4

So:

Length = 8 + 2

Length = 10

Width = 16 + 4

Width = 20

To double-check;

Differentiate A'

A' = -512y^{-2} + 2

A" = -2 * -512y^{-3}

A" = 1024y^{-3}

A" = \frac{1024}{y^3}

The above value is:

A" = \frac{1024}{y^3} > 0

This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

3 0
3 years ago
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oksano4ka [1.4K]

Answer:

No.

Step-by-step explanation:

3/4 is not less than 2/10.

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2/10 = 4/20

15/20 > 4/20

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Answer:

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Step-by-step explanation:

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