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enyata [817]
3 years ago
6

Please help me w khan

Mathematics
1 answer:
Zanzabum3 years ago
4 0

Answer:

A

Step-by-step explanation:

Graph A represents a linear equation. This means that a certain number of teams join every week. For example, (0,6)(1,12)(2,18) etc... Therefore, graph A is correct.

Graph B represents an exponential equation. This means that the number of teams is multiplied every week. For example, (0,6)(1,36)(2,216) etc...

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What is the prim fractorization of 3456
Leviafan [203]

The Prime Factorization is:

2 x 3 x 17 x 23

In Exponential Form:

21 x 31 x 171 x 231

CSV Format:

2, 3, 17, 23

Prime Factors Tree

 2346      

 /  \      

2   1173    

   /  \    

 3   391  

     /  \  

         17   23


5 0
3 years ago
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Dawn earned $97.50 for 10 hours of work. Amy earned $120 for 12 hours of work. How much did each person earn per hour?
Galina-37 [17]
Dawn heard 9.75 a hour and Amy earns 10 a hour
8 0
3 years ago
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Urgent please help with finding rate of change
boyakko [2]

When working with functions (of all types), the average rate of change is expressed using function notation:

\dfrac{f(b)-f(a)}{b-a}.

For the interval from x=7 to x=8,

1. find f(7) and f(8):

  • f(7)=729\cdot 3=2187;
  • f(8)=2187\cdot 3=6561;

2. use given formula:

\dfrac{f(8)-f(7)}{8-7}=\dfrac{6561-2187}{8-7}=4374.

Answer: the average rate of change for the interval from x=7 to x=8 is 4374.

5 0
3 years ago
Two cars are driving away from an intersection in perpendicular directions. The first car's velocity is 777 meters per second an
salantis [7]

Answer:

The rate of change of the distance between the cars at that instant is 5.46 meters per second

Step-by-step explanation:

Speed of first car = 7 m/s

Speed of second car = 3 m/s

At instant, distance of first car from intersection = 5 meters

distance of second car from intersection = 12 meters

Therefore, we have

Distance between both cars at intant = √(12² + 5²) = 13 m

Rate of cahnge of distance is given by;

2ddd/dt = d(x² + y²)/dt = 2xdx/dt + 2ydy/dt

= 26dd/dt = 2×5×7 + 2×12×3 = 142

dd/dt = 142/26 = 5.46 m/s.

That is the rate of change of the distance between the cars at that instant = 5.46 meters per second.

7 0
3 years ago
How many more pieces did the 40 pound pumpkin smash into than the 30 pound pumpkin
yaroslaw [1]
Im pretty sure it would be 10??? if you are putting it as a subtraction problem if not i would try wording it more clearly
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3 years ago
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