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Sati [7]
3 years ago
12

which function results after applying the sequence of transformations to f(x)=x^5 reflect over the y axis ; shift 1 unit left ;

vertically compress by 1/3
Mathematics
2 answers:
Morgarella [4.7K]3 years ago
6 0
For this case we have the following function:
 f (x) = x ^ 5
 We apply the following transformations:
 reflect over the y axis:
 f (x) = (- x) ^ 5
 shift 1 unit left:
 f (x) = (- x + 1) ^ 5
 vertically compress by 1/3:
 f (x) = (1/3) (- x + 1) ^ 5
 Answer:
 
A function that results after applying the sequence of transformations is:
 
f (x) = (1/3) (- x + 1) ^ 5
Reika [66]3 years ago
5 0
The correct answer is f(x)=1/3(-x+1)^5. All the other answers show no reflect that match the f(x)=x^5.
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hoa [83]
-2x + 5 < 7

-2x + 5 < 7
<u>        -5     -5   </u>       deduct 5 from both sides
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The value of x should be greater than -1. It can be 0, 1, 2, so on... 

To check: Revert back to the original sign which is <.

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zepelin [54]

Answer:

x = √(3^125/ 5)

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x^2 = 3^125/ 5

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