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Sati [7]
3 years ago
12

which function results after applying the sequence of transformations to f(x)=x^5 reflect over the y axis ; shift 1 unit left ;

vertically compress by 1/3
Mathematics
2 answers:
Morgarella [4.7K]3 years ago
6 0
For this case we have the following function:
 f (x) = x ^ 5
 We apply the following transformations:
 reflect over the y axis:
 f (x) = (- x) ^ 5
 shift 1 unit left:
 f (x) = (- x + 1) ^ 5
 vertically compress by 1/3:
 f (x) = (1/3) (- x + 1) ^ 5
 Answer:
 
A function that results after applying the sequence of transformations is:
 
f (x) = (1/3) (- x + 1) ^ 5
Reika [66]3 years ago
5 0
The correct answer is f(x)=1/3(-x+1)^5. All the other answers show no reflect that match the f(x)=x^5.
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3 years ago
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Elodia [21]

All exercises involve the same concept, so I'll show you how to do the first, then you can apply the exact same logic to all the others.

The first thing you need to know is that, when a certain quantity multiplies a parenthesis, you can distribute that number to every element in the parenthesis. This means that

a(b+c) = ab+ac

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Secondly, you have to know how to recognize like terms, because they are the only terms you can sum. Two terms can be summed if they have the same literal expression. So, for example, you cannot sum 3x+2y, and neither 5x^2-4x exponents count.

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So, take for example exercise 9:

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Hunter-Best [27]

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====================================================

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