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Sati [7]
4 years ago
12

which function results after applying the sequence of transformations to f(x)=x^5 reflect over the y axis ; shift 1 unit left ;

vertically compress by 1/3
Mathematics
2 answers:
Morgarella [4.7K]4 years ago
6 0
For this case we have the following function:
 f (x) = x ^ 5
 We apply the following transformations:
 reflect over the y axis:
 f (x) = (- x) ^ 5
 shift 1 unit left:
 f (x) = (- x + 1) ^ 5
 vertically compress by 1/3:
 f (x) = (1/3) (- x + 1) ^ 5
 Answer:
 
A function that results after applying the sequence of transformations is:
 
f (x) = (1/3) (- x + 1) ^ 5
Reika [66]4 years ago
5 0
The correct answer is f(x)=1/3(-x+1)^5. All the other answers show no reflect that match the f(x)=x^5.
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Which expressions are equivalent to 2(2x + 4y + x − 2y)?
joja [24]

Answer: 2(3x + 2y) and 6x + 4y

Step-by-step explanation:

Hi, to answer this question we have to solve the expression.

2(2x + 4y + x − 2y)

First we have to simplify the expression within the brackets.

2 (2x + x +4y -2y)

  • 2( 3x + 2y)

We have the first equivalent expression. Now to obtain the second expression we apply distributive property:

2 (3x) + 2 ( 2y)

  • 6x + 4y

In conclusion 2(3x + 2y) and 6x + 4y are equivalent expressions to 2(2x + 4y + x − 2y).

Feel free to ask for more if it´s necessary or if you did not understand something.

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