All categories

3 years ago

Please answer all of these questions for me, it would mean the world to me!

Mathematics

2 answers:

sineoko [7]3 years ago

5 0

Answer:

2+2=4

Step-by-step explanation: btw what questions?

riadik2000 [5.3K]3 years ago

3 0

Answer:

Wait, wheres the questions?

Step-by-step explanation:

You might be interested in

Evaluate \dfrac{e}{4}+2f-3 4e +2f−3 when e=12e=12 and f=\dfrac12f= 21<br>

dusya [7]

Answer:

\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left(-10-\left(-6\right)\right)}{\frac{\left(4+5\right)}{\left(4^2-3^2\left(4-3\right)-8\right)}+12}=5

Step-by-step explanation:

7 0

3 years ago

Find the condition that one root of the quadratic equation may be 1 more than the other.

Eddi Din [679]

<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>

4 0

3 years ago

What is the value of the expression 9+4n-1 when n = 3?

dangina [55]

Answer: 9+4n-1 = 20

We can solve this by substitution.
Replace n with the value given, 3 (remember 4n means 4 times n):
9 + 4*3 - 1
Then work it out using arithmetic
9+12-1
=20

6 0

2 years ago

Two positive integers are 3 units apart on a number line. Their product is 108. Which equation can be used to solve for m, the g

nikitadnepr [17]

If the greater integer is m, then the smaller integer must be (m-3) because the integers are 3 units apart on a number line. It cannot be in front of m, because m is the greater so it must be behind m meaning it is 3 units less. Product is the technical term for the result of a multiplication problem so m(m-3) = 108 would be the answer.

Final Answer: m(m-3) = 108

8 0

3 years ago

Read 2 more answers

Determine whether quadrilateral ABCD is a rhombus, a rectangle, a square, a parallelogram, or none. List all that apply. Explain

svlad2 [7]

Answer:

ABCD is a rhombus, and a parallelogram

==================================

<h3>Given </h3>

Points A(-6, - 1), B(4, - 6), C(2, 5), D(- 8, 10)

First, plot the points (see attached picture).

Then, connect all the points.

Opposite sides are parallel,
Diagonals are perpendicular.

From our observation the figure is rhombus.

Let's confirm it with the following.

1) Find midpoints of diagonals and compare.

AC → x = (- 6 + 2)/2 = - 2, y = (- 1 + 5)/2 = 2
BD → x = (4 - 8)/2 = - 2, y = (- 6 + 10)/2 = 2

The midpoint of both diagonals is same (- 2, 2).

2) Find slopes of diagonals and check if their product is -1, this will confirm they are perpendicular.

m(AC) = (5 - (-1))/(2 - (-6)) = 6/8 = 3/4
m(BD) = (10 - (-6))/(-8 - 4) = - 16/12 = - 4/3

m(AC) × m(BD) = 3/4 * (- 4/3) = - 1

<u>Confirmed.</u>

So this is a rhombus and also a parallelogram but <u>not</u> rectangle or square, since opposite angles are not right angles.

5 0

1 year ago