Kayla saves $110 to purchase a new outfit. She decides to but a skirt for $29.65, a sweater for $38.32, and a purse for $31.00

How do the 2 triangles formed compare to each other?

rjkz [21]

Answer: there is no picture to see what they look like

Step-by-step explanation: if you are on computer, upload the picture so we can solve your question.

5 0

3 years ago

Let divf = 6(5 − x) and 0 ≤ a, b, c ≤ 12. (a) find the flux of f out of the rectangular solid 0 ≤ x ≤ a, 0 ≤ y ≤ b, and 0 ≤ z ≤

dusya [7]

Continuing from the setup in the question linked above (and using the same symbols/variables), we have

$\displaystyle\iint_{\mathcal S}\mathbf f\cdot\mathrm d\mathbf S=\iiint_{\mathcal R}(\nabla\cdot f)\,\mathrm dV$
$=\displaystyle6\int_{z=0}^{z=c}\int_{y=0}^{y=b}\int_{x=0}^{x=a}(5-x)\,\mathrm dx\,\mathrm dy\,\mathrm dz$
$=\displaystyle6bc\int_0^a(5-x)\,\mathrm dx$
$=6bc\left(5a-\dfrac{a^2}2\right)=3abc(10-a)$

The next part of the question asks to maximize this result - our target function which we'll call $g(a,b,c)=3abc(10-a)$ - subject to $0\le a,b,c\le12$ .

We can see that $g$ is quadratic in $a$ , so let's complete the square.

$g(a,b,c)=-3bc(a^2-10a+25-25)=3bc(25-(a-5)^2)$

Since $b,c$ are non-negative, it stands to reason that the total product will be maximized if $a-5$ vanishes because $25-(a-5)^2$ is a parabola with its vertex (a maximum) at (5, 25). Setting $a=5$ , it's clear that the maximum of $g$ will then be attained when $b,c$ are largest, so the largest flux will be attained at $(a,b,c)=(5,12,12)$ , which gives a flux of 10,800.

7 0

3 years ago

the length of a rectangle is twice its width. the perimeter of the rectangle is no more than 174cm. what is the greatest possibl

Feliz [49]

Hey there
I 've already answered this question twice
by mistake.Kindly check.

4 0

3 years ago

Add.<br> (4x2 - 2x) + (5x-7)

Sloan [31]

Answer:

4x²+3x-7 is the answer

Step-by-step explanation:

=(4x²-2x)+(5x-7)

opening brackets

=4x²-2x+5x-7

=4x²+3x-7

i hope this will help you :)

7 0

4 years ago

I need help with no.7

ziro4ka [17]

Answer:

(a) 315°

(b) 3°

(c) 238°

Step-by-step explanation:

Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.

The bearing of P from R is 180° different from the bearing of R from P it will be ...

135° +180° = 315° . . . . bearing of P from R

__

The bearing of Q from R is 48° more than the bearing of P from R, so is ...

315° +48° = 363°, or 3° . . . . bearing of Q from R

__

The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...

180° -48° -55° = 77°

The bearing of Q from P is 77° less than the bearing of R from P, so is ...

135° -77° = 58°

As above, the reverse bearing from Q to P is ...

58° +180° = 238° . . . . bearing of P from Q

8 0

3 years ago