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inna [77]
3 years ago
7

It is used to replace numeric number of a website​

Computers and Technology
1 answer:
vampirchik [111]3 years ago
5 0

greatflombles or gr8flombles or go2flombles

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PLEASE HELP ASAP!!!!!!!!!! WILL GIVE A BRAINLIEST!!!!!!
sattari [20]
The answer to this question is:

"Both work with computers, but only Bluetooth can be used in a headset"

The answer to this is true because Both computers can use/work with computer but Bluetooth can only connect to head set headset don't need wifi it needs Bluetooth and charging/plug

Your Welcome :)
5 0
3 years ago
Read 2 more answers
In Java, write a AllDigitsOdd program that has a method called allDigitsOdd that takes an integer and returns whether every digi
yan [13]

Answer:

Hi there! The solution for this problem can be implemented a number of ways. Please find my solution below along with the explanation.

Explanation:

The prompts are fairly easily implemented using the Scanner class in Java for user input. In the allDigitsOdd function, we can perform a Math operation on the number being passed into the function to determine the number of digits in the number. We use the log10 function to do this and convert the double value returned to int. This is calculated in the code below as:  "(int)(Math.log10(number) + 1); ". Once we have the number of digits, we write a simple loop to iterate over each digit and perform a modulus function on it to determine if the digit is odd or even. I have declared 2 variables call odd and even that get incremented if the mod function (%) returns a 1 or a 0 respectively. Finally, the result is displayed on the screen.

AllDigitsOdd.java

import java.util.Scanner;

import java.lang.Math;

public class AllDigitsOdd {

 public static void main(String args[]) {

   // print main menu for user selection

   System.out.println("Please enter a number");

   Scanner scan = new Scanner(System.in);

   int selection = scan.nextInt();

   if (allDigitsOdd(selection)) {

     System.out.println("All numbers are odd");

   } else {

     System.out.println("All numbers are not odd");

   }

 }

 public static boolean allDigitsOdd(int number) {

   int digits = (int)(Math.log10(number) + 1);

   int even = 0;

   int odd = 0;

   for (int index = 1; index <= digits; index++) {

       if ((int)(number / Math.pow(10, index - 1)) % 10 % 2 == 0) {

         even += 1;

       } else {

         odd += 1;

       }

   }

   if (even == 0 && odd > 0) {

     return true;

   } else {

     return false;

     //if (odd > 0 && even == 0) {

     //  return true;

     //}

   }

 }

}

8 0
3 years ago
How long does the Splunk search job remain active
Degger [83]
When you run a new search job, the job is retained in the system for a period of time, called the job lifetime. f the job is not accessed within the specified lifetime, the job expires and is removed from the system. There are two lifetime settings, 10 minutes and 7 days. The lifetime starts from the moment the job is run.
8 0
3 years ago
Graphics you can select to reinforce the goal of your document include ____.
Tanya [424]
The answer would be D all of the above.
8 0
3 years ago
How to 5.4.4 on codehs?
iren2701 [21]

The program is an illustration of the square function.

The square function takes a number, and returns the square of the number; i.e. the product of the number twice.

So, the square function in Python, where comments are used to explain each line is as follows:

#This defines the square function

def square(num):

   #This returns the square of the argument

   return num**2

   

#This gets input for the number

num = int(input("Number: "))

#This calculates the square of the number

x = square(num)

#This prints the square

print("Square:",x)

Read more about Python functions at:

brainly.com/question/25120954

3 0
2 years ago
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