Answer:
Option d) B is 1.33 times faster than A
Given:
Clock time, 

No. of cycles per instructions, 

Solution:
Let I be the no. of instructions for the program.
CPU clock cycle,
= 2.0 I
CPU clock cycle,
= 1.0 I
Now,
CPU time for each can be calculated as:
CPU time, T = 


Thus B is faster than A
Now,


Performance of B is 1.33 times that of A
Access to 4 gigabytes of memory
The first division should reduce the hundreds digit to the units digit by dividing by 100. Ignoring remainder means ignoring the previous units and tens digits.
The second division, where we keep the remainder is to extract the units digit by ignoring the quotient. So we divide by 10. The discarded digits are the tens and higher digits.