Answer:
A
Explanation:
thethe more you have attached the more people are going to know your product so that it's going to be a long process which people can introduce to their friends
The answer & explanation for this question is given in the attachment below.
Answer:
c,a,c using the drop down menus edge 2021
GOODLUCK
Explanation:
Answer:
The program to this question can be given as:
Program:
public class Main //define class.
{
public static void main(String[] as) //define main method.
{
int n=5; //define variable n and assign positive value.
int i,j; //define variable
for (i = 7; i>=1; i--) //outer loop.
{
for (j = 0; j< i; j++) //inner loop.
{
System.out.print("*"); //print asterisks.
}
System.out.println(); //line break.
}
}
}
Output:
*****
****
***
**
*
Explanation:
The description of the above code can be given as:
- In the above java programming code firstly we define a class that is "Main". In this class we define a main method in the main method we define a variables that is "n" in this variable we assign a positive value. The we define another integer variable that is i,j this variable is used in the loop.
- Then we define a loop. for prints asterisks values in reverse triangle, we nested looping concept. In nested looping, we use in loop in this loop we use the i and j variables that print the asterisks value.
Answer:
206.58.170.67 is the decimal format of the given binary IP address.
Explanation:
we can convert the binary number into decimal by the following procedure.
11001110 = 1x2⁷+1x2⁶+0x2⁵+0x2⁴+1x2³+1x2²+1x2¹+0x2⁰
= 128 + 64 + 0 + 0 + 8 + 4 + 2 + 0
= 206
00111010 = 0x2⁷+0x2⁶+1x2⁵+ 1x2⁴+1x2³+0x2²+1x2¹+0x2⁰
= 0 + 0 + 32 + 16 + 8 + 0 + 2 + 0
= 58
10101010 = 1x2⁷+0x2⁶+1x2⁵+ 0x2⁴+1x2³+0x2²+1x2¹+0x2⁰
= 128 + 0 + 32 + 0 + 8 + 0 + 2 + 0
= 170
01000011 = 0x2⁷+ 1x2⁶+ 0x2⁵+ 0x2⁴+ 0x2³+0x2²+1x2¹+1x2⁰
= 0 + 64 + 0 + 0 + 0 + 0 + 2 + 1
= 67
so, the IP address is becomes 206.58.170.67
