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ruslelena [56]
3 years ago
11

2 (5 – a) – 6 (2a + 3)

Mathematics
1 answer:
GaryK [48]3 years ago
4 0

Answer: -14a - 8

Step-by-step explanation:

so basically... idek

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I Need The Answer Plz!! Geometry is tuff
melamori03 [73]

Answer: F-H      G-F      G-H

Step-by-step explanation:

5 0
3 years ago
Is there a relationship between the distance and the sum? Is there a relationship between the distance and the difference?
ivann1987 [24]

Answer:

The distance is the absolute value of the difference.

Step-by-step explanation:

I know things : )

8 0
3 years ago
A culture started with 2000 bacteria after 5 hours it grew to 2600
Jobisdone [24]
P(t) = P₀ e^(kt) 

<span>Where P₀ is the initial population, </span>
<span>P(t) is the population after "t" time. </span>
<span>t is your rate (can be hours, days, years, etc. in this case, hours) </span>
<span>k is the growth constant for this particular problem. </span>

<span>So using the information given, solve for k: </span>

<span>P₀ = 2000 </span>
<span>P(4) = 2600 </span>

<span>P(t) = P₀ e^(kt) </span>
<span>2600 = 2000e^(k * 4) </span>
<span>1.3 = e^(4k) </span>

<span>Natural log of both sides: </span>

<span>ln(1.3) = 4k </span>
<span>k = ln(1.3) / 4 </span>

<span>Now that we have a value for "k", use that, the same P₀, then solve for P(17): </span>

<span>P(t) = P₀ e^(kt) </span>
<span>P(17) = 2000 e^(17ln(1.3) / 4) </span>

<span>Using a calculator to get ln(1.3) then to simplify from there, we get: </span>

<span>P(17) ≈ 2000 e^(17 * 0.262364 / 4) </span>
<span>P(17) ≈ 2000 e^(4.460188 / 4) </span>
<span>P(17) ≈ 2000 e^(1.115047) </span>
<span>P(17) ≈ 2000 * 3.0497 </span>
<span>P(17) ≈ 6099.4 </span>

<span>Rounded to the nearest unit: </span>

<span>P(17) ≈ 6099 bacteria  hope i could help =)))</span>
3 0
3 years ago
Find the total cost of an item after tax if the item is $75 and sales tax is 8%?
lianna [129]

Answer:$81

explanation:

8% of 75 is 6

75+6= 81

Answer ($81)

7 0
3 years ago
Read 2 more answers
This system has one solution.
mel-nik [20]

Answer:

<h2>y = 2</h2>

Step-by-step explanation:

y=8x-14\qquad(1)\\y=x^2+4x-10\qquad(2)\\\\\text{compare equations}\\\\x^2+4x-10=8x-14\qquad\text{subtract 8x from both sides}\\\\x^2-4x-10=-14\qquad\text{add 14 to both sides}\\\\x^2-4x+4=0\\\\x^2-2x-2x+4=0\\\\x(x-2)-2(x-2)=0\\\\(x-2)(x-2)=0\\\\(x-2)^2=0\iff x-2=0\qquad\text{add 2 to both sides}\\\\x=2\\\\\text{Put the value of x to (1)}:\\\\y=8(2)-14=16-14=2

4 0
3 years ago
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