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Mrrafil [7]
2 years ago
12

Daniel invests £2200 into his bank account.

Mathematics
1 answer:
Snowcat [4.5K]2 years ago
7 0

Answer:

I = $ 220.00

Step-by-step explanation:

I = $ 220.00

Equation:

I = Prt

Solve:

First, converting R percent to r a decimal

r = R/100 = 5%/100 = 0.05 per year,

then, solving our equation

I = 2200 × 0.05 × 2 = 220

I = $ 220.00

The simple interest accumulated

on a principal of $ 2,200.00

at a rate of 5% per year

for 2 years is $ 220.00.

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Answer:

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Step-by-step explanation:

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Answer:

(2m - 7)(4 {m}^{2}  + 3)

Step-by-step explanation:

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If the slope of a line is 2 and its y-intercept is 5, what is the equation of the line?
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3 years ago
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If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°
Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = c^{2} = a^{2} + b^{2}

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a^{2} = 49

b^{2} = 121

Plugging in the values, we will get:

c^{2} = 49 + 121

c^{2} = 170

c = \sqrt{170}

To calculate the unknown angle B, we can use law of sine.

Law of sine = \frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

So,

\frac{c}{sinC} = \frac{b}{sinB}

\frac{\sqrt{170} }{sin90} =  \frac{11}{sinB}

Sin90 = 1

sinB = \frac{11}{\sqrt{170} }

B = sin^{-1} (\frac{11}{\sqrt{170} })

B = 57.5°

8 0
3 years ago
∆ABC is reflected about the line y = -x to give ∆A'B'C' with vertices
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Since A‘(-1,1) is on the line y=-x, reflecting it about the line doesn't change its coordinate, so A's coordinate is (-1,1). Reflecting B'(-2,1) about y=-x switches both the sign and the number of x and y, so B=(-1,2), and C'(-1,0) becomes C(0,1). Drawing out the graph with the points and the line helps.
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