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fenix001 [56]
3 years ago
13

6.1.PS-17

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
5 0
19/25 or 76/100 so it would be 76%
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If a point is the midpoint of a segment, then it divides the segment into two congruent segments. R is the midpoint of QS. Concl
DIA [1.3K]

Answer:

All given information leads to conclusion described on statement. (QR = RS)

Step-by-step explanation:

The strategy of problem consist in make a mathematical demonstration from given information. There are two assumptions: i) R is a point of segment QS and ii) R is the midpoint of QS. We proceed to perform the demonstration:

1) R\in QS, R is the midpoint of QS. Given.

2) Q - R = R -S Definition of midpoint.

3) QR = RS Definition of segment/Result.

All given information leads to conclusion described on statement. (QR = RS)

8 0
3 years ago
Which of the following are exterior angles? Check all that apply.
Marina86 [1]

Answer:

A

C

D

E

Step-by-step explanation:

Exterior angles can be described as the angles that are formed between the side of a polygon and the extended adjacent side of the polygon.

Or an exterior angle is the angle that is not inside the triangle formed.

The angles inside the triangle are interior angles.

Exterior angles are :

2

3

4

6

Interior angles are :

1

5

6 0
3 years ago
The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
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Segment AE is a median for Triangle ABC.
Shalnov [3]

Step-by-step explanation:

BC = BE + CE...(\because B-E-C)  \\  \\  \therefore \: BC = 3x - 5 + x + 1 \\  \\ \therefore \: BC = 4x - 4 \\  \\  \huge \red{ \boxed{ \therefore \: BC = 4(x - 1)}}

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4 years ago
Ayo, here are some points.<br> Also- what's an unpopular opinion you have? About anything.
Sati [7]

Answer:

hli

Step-by-step explanation:

how r u dear hope u r fine

3 0
2 years ago
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