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MakcuM [25]
3 years ago
13

4x5

nfty%7D%20a_n%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D" id="TexFormula1" title="\sqrt[n]{x} \sqrt{x} x^{2} \\ \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]" alt="\sqrt[n]{x} \sqrt{x} x^{2} \\ \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Contact [7]3 years ago
4 0
Your answer is 20

Hope this helps good luck
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Please help
Korvikt [17]

Answer:

b. c(p) = 0.42p

Step-by-step explanation:

you are multiplying the cost (0.42) by the pounds (p)

7 0
3 years ago
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Solve for x.<br> (1/3) over 3 =x over 8
Ugo [173]

8/3=3x (cross multiplied to get this)

X=8/9 (divided both sides by 3)

Hope this helps :)

8 0
3 years ago
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A group of 4 friends likes to bowl together, and each friend keeps track of his all-time highest score in a single game. Their h
andre [41]
I believe C is the answer, hope this helps!
4 0
3 years ago
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11-Determine the specific heat of a material if a 12-g sample absorbed 96 J as it was heated from 20°C to 40°C. *
kompoz [17]

Answer:

c=0.4\ J/g^{\circ} C

Step-by-step explanation:

Given that,

Mass of a sample, m = 12 g

Heat absobed by the sample, Q = 96 J

It was heated from 20°C to 40°C.

We need to find the specific heat of a material. The heat absorbed by a sample is given by :

Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{96}{12\times (40-20)}\\\\=0.4\ J/g^{\circ} C

So, the specific heat of the material is 0.4\ J/g^{\circ} C.

3 0
3 years ago
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sukhopar [10]

Answer:

30 degress

Step-by-step explanation:

6 0
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