1. No answer ( may be due to incorrect question)
2. x = -3
y = 4
3. x= 4
y = 2
4.x = -63/40
y= -19/20
Step 1
Multiply equation 1 by the coefficient of x in equation 2
Multiply equation 2 by the coefficient of x I'm equation 1
(after completing this step you will derive equation 3 and 4 )
Step 2
Subtract equation 4 from equation 3
Step 3
Divide both sides of the equation by the coefficient of y
Step 4
substitute your value for y in equation 1 or 2
(after this you will derive the values of x)
Note : This method is for the Elimination of x
I hope it helps
Answer:
D. x = 10, m<TRS = 60°
Step-by-step explanation:
m<QRS = 122° (given)
m<QRT = (7x - 8)° (given)
m<TRS = (6x)° (given)
m<QRT + m<TRS = m<QRS (angle addition postulate)
(7x - 8)° + (6x)° = 122° (substitution)
Solve for x
7x - 8 + 6x = 122
Add like terms
13x - 8 = 122
13x = 122 + 8
13x = 130
x = 130/13
x = 10
✔️m<TRS = (6x)°
Plug in the value of x
m<TRS = (6*10)° = 60°
Answer:
After simplifying we get (x,y) as (1,3).
Step-by-step explanation:
Given:
,
We need to use elimination method to solve the and simplify the equations.
Solution;
Let ⇒ equation 1
Also Let 
⇒ equation 2
Now by solving the equation we get;
first we will Add equation 2 from equation 1 we get;
Now Dividing both side by 5 using division property of equality we get;
Now Substituting the vale of x in equation 1 we get;
subtracting both side by 1 using subtraction property of equality we get;
Now Dividing both side by 7 using division property of equality we get;
Hence we can say that, After simplifying we get (x,y) as (1,3).
Answer:
Option C.
Step-by-step explanation:
Total population = 1000 snails
AA = 160 snails
Aa = 480 snails
aa = 360 snails
Frequency of each type.
Now, we get
he frequency of the A allele in this population is 0.4.
Therefore, the correct option is C.
Answer:
this is unsolvable i think
Step-by-step explanation:
