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3 years ago

How much force was applied to a 5 kg object if it accelerated by 15 m/s/s

Mathematics

2 answers:

REY [17]3 years ago

8 0

Answer:

We use Newton's second law of motion, which states that,

where:

is the net force applied in newtons

is the mass of the object in kilograms

is the acceleration of the object in meters per second squared

So, we get:

⋅

m/s

(

∵

≡

kg m/s

)

Step-by-step explanation:

raketka [301]3 years ago

8 0

Answer:

75 Newtons

Step-by-step explanation:

By Newtons Second Law

Force F = mass * acceleration

So F = 5 * 15 = 75 N.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Find:-

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$M = 2*\int\limits_0^\pi {[ 121.5r^2-r^3 -\frac{161r^4}{162} ] } |_0^6 \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 121.5(6)^2-(6)^3 -\frac{161(6)^4}{162} ] } \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 4375-216 -1288] } \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 2871] } \, dtheta\\\\M = 5742\pi kg$

- The mass evaluated is M = 5742π

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