All categories

3 years ago

Jordan bought a magazine for $6 and some

Mathematics

2 answers:

Nookie1986 [14]3 years ago

7 0

Answer:

she bought 4 notebooks

Step-by-step explanation:

3x4=12+6=18

blondinia [14]3 years ago

6 0

Answer:

Step-by-step explanation:

18-6=12

You might be interested in

Nina can braid 48 inches of rope in 1 hour. what is her speed in feet per hour?

mr Goodwill [35]

There are 4 feet in 48 inches, so your answer should just be 4 feet per hour.

3 0

3 years ago

PLS HELP ME! FOR 50 POINTS!!! I will give brainliest!

lbvjy [14]

Answer:

$\frac{x - 3}{x + 4} \div \frac{x ^{2} - 1 }{ x} \\ = \frac{x - 3}{x + 4} \times \frac{x}{ {x}^{2} - 1} \\ =\frac{x(x - 3)}{(x + 4)( {x}^{2} - 1) } \\= \frac{x(x - 3)}{(x + 4)(x + 1)(x - 1)}$

8 0

3 years ago

We are more aware of the _ form than the _ spaces

devlian [24]

The answer is: We are more aware of the positive form than the negative spaces. In which with every movement, the connection of form and space modify. A creator should possess every angle in mind in which the form is being created and the spaces adjoining the form. Space may comprise curls, the curves, the waves, the straight hair or any arrangement. In general, it is the space which is the area surrounding the form or area that the style occupies.

8 0

3 years ago

An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

A red ball drawn first, there are $E(1)= ^9C_2$ places in which the other 2 red balls can be placed.

A red ball drawn third, there are $E(3)= ^7C_2$ places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are $E(5)= ^5C_2$ places in which the other 2 red balls can be placed.

A red ball drawn seventh, there are $E(7)= ^3C_2$ places in which the other 2 red balls can be placed.

The total number of total event is $S= ^{10}C_3$

The probability that A selects the first red ball is

$P(A \text{wins})=\frac{(^9C_2)+(^7C_2)+(^5C_2)+(^3C_2)}{^{10}C_3}$

$P(A \text{wins})=\frac{36+21+10+3}{120}$

$P(A \text{wins})=\frac{70}{120}$

$P(A \text{wins})=0.5833$

6 0

3 years ago

A candle in the shape of a circular cone has a base of radius r and a height of h that is the same length as the radius. which e

ladessa [460]

Answer:

$\frac{r(1-\sqrt{2})}{-3}$

Step-by-step explanation:

Volume of cone = $\frac{1}{3} \pi r^{2} h$

Since we are given that a circular cone has a base of radius r and a height of h that is the same length as the radius

= $\frac{1}{3} \pi r^{2} \times r$

= $\frac{1}{3} \pi r^{3}$

Surface area of cone including 1 base = $\pi r^{2} +\pi\times r \times \sqrt{r^2+h^2}$

Since r = h

So, area = $\pi r^{2} +\pi\times r \times \sqrt{r^2+r^2}$

= $\pi r^{2} +\pi\times r \times \sqrt{2r^2}$

= $\pi r^{2} +\pi\times r^2 \times \sqrt{2}$

Ratio of volume of cone to its surface area including base :

$\frac{\frac{1}{3} \pi r^{3}}{\pi r^{2} +\pi\times r^2 \times \sqrt{2}}$

$\frac{\frac{1}{3}r}{1+\sqrt{2}}$

$\frac{r}{3(1+\sqrt{2})}$

Rationalizing

$\frac{r}{3(1+\sqrt{2})} \times \frac{1-\sqrt{2}}{1-\sqrt{2}}$

$\frac{r(1-\sqrt{2})}{-3}$

Hence the ratio the ratio of the volume of the candle to its surface area(including the base) is $\frac{r(1-\sqrt{2})}{-3}$

8 0

3 years ago

Read 2 more answers