Missing data:
Viewer's Age Group Excellent Good Average Poor Marginal Total
16–25 52 42 12 7 113
26–35 33 50 5 9 97
36–45 58 12 28 34 132
46–55 25 17 22 12 76
56 + 12 5 3 8 28
Marginal Total 180 126 70 70 446
A rating of good or excellent indicates the audience liked the movie, while a rating of poor indicates the audience disliked the movie.
<h3>How to determine the rating of the film from the 46–55 age group?</h3>
A movie producer accomplished a survey behind a preview screening of her latest movie to estimate how the film would be accepted by viewers from various age groups. The table displays the numbers of viewers in various age groups who ranked the film excellent, good, average, and poor.
25/446 = 0.05605
0.05605 
100% = 5.605%
Out of the entire respondents, the percentage of respondents from the 46–55 age group who ranked the film excellent exists at 5.605%.
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Answer:
2
Step-by-step explanation:
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The question was incorrect. Please find the correct content below.
Compare 32/35 and 9/10.
Comparing 32/35 and 9/10 we have 32/35 is greater than 9/10, that is 32/35 > 9/10.
Fraction is the ratio of two numbers. The upper number is called Numerator and the Lower number is called the Denominator.
We know that if the denominators are the same for two fractions then which has the greatest numerator is a greater fraction than the other.
Given the fractions are 32/35, 9/10
To compare this two fractions we have to make denominators equal first.
LCM of 10,35 = 70
Calculating the fractions,
32/35 = (32*2)/(35*2) = 64/70
9/10 = (9*7)/(10*7) = 63/70
Since 64 > 63
So 64/70 > 63/70
Therefore, 32/35 > 9/10
Hence fraction 32/35 is greater than the other fraction 9/10.
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you can only see values of 
Ranging from $-3$ to $3$ and they're included, so domain is $[-3,3]$
and $y$ values ranging from $-2$ to $4$ but $-2$ is not included so range is $(-2,4]$
Answer:
Step-by-step explanation:
-5x - 8y = -3
5x + 9y = 3
y = 0
5x + 0 = 3
5x = 3
x = 3/5
(3/5, 0)
