Answer:
m∠BOC = 40°
Step-by-step explanation:
Given O A ‾ ⊥ O C ‾ OA ⊥ OC m∠BOC=6x−6 ∘
m∠AOB=5x+8 ∘
Find m ∠ B O C:
This means that: m∠BOC and m∠AOC intersect at a right angle.
Hence:
m∠BOC + m∠AOC = 90°
Step 1
Solving for x
6x - 6 + 5x + 8 = 90°
11x -2 = 90°
11x = 90 - 2
11x = 88
x = 88/11
x = 8
Step 2
Solving for m∠BOC
m∠BOC = 6x - 8
m∠BOC = 6(8) - 8
= 48 - 8
= 40°
We are given that the
coordinates of the vertices of the rhombus are:
<span><span>A(-6, 3)
B(-4, 4)
C(-2, 3)
D(-4, 2)
To solve this problem, we must plot this on a graphing paper or graphing
calculator to clearly see the movement of the graph. If we transform this by
doing a counterclockwise rotation, then the result would be:
</span>A(-6, -3)</span>
B(-4, -4)
C(-2, -3)
D(-4, -2)
And the final
transformation is translation by 3 units left and 2 units down. This can still
be clearly solved by actually graphing the plot. The result of this
transformation would be:
<span>A′(6, -8)
B′(7, -6)
C′(6, -4)
D′(5, -6)</span>
Answer:
Step-by-step explanation:
(35 - 20)/20
15/20 = .75
.75 * 100 == 75%
75%
Answer:
20%
Step-by-step explanation:
Just did the question :)
