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USPshnik [31]
4 years ago
13

-6+5x=6x-3 i need help trying to solve this step by step

Mathematics
2 answers:
antiseptic1488 [7]4 years ago
5 0

Answer:

X= -3

Step-by-step explanation:

Add 6 to both sides

-6+5x+6=6x-3+6

simplify

5x=6x+3

subtract 6x from both sides

5x-6x=6x+3-6x

simplify

-x=3

divide both sides by -1

-x/-1=3/-1

simplify

x= -3

slamgirl [31]4 years ago
4 0

Answer: x=-3

Step-by-step explanation:

-6 + 5x=6x-3

-3 +5x=6x

-3=x

x=-3

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weqwewe [10]
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If the roots of x²-7x+k=0 are m and m-1, find the value of the constant k​
creativ13 [48]

Answer: k=12

Step-by-step explanation:

x2 - 7x + k = 0

using quadratic formula method,

x = [-b ± √(b2 - 4ac)]/2a

a = 1

b = -7

c = k

x = [-(-7) ± √((-7)2 - 4(1)(k))]/2(1)

x = [7 ± √(49 - 4k)]/2

x = [7 + √(49 - 4k)] / 2 and [7 - √(49 - 4k)] / 2

since the roots are m and m-1,

m = [7 + √(49 - 4k)] / 2 ------------ eqn(1), and

m - 1 = [7 - √(49 - 4k)] / 2 ----------- eqn(2)

add 1 to both sides of eqn(2)

m = [7 - √(49 - 4k)]/2 + 1 --------------- eqn(3)

eqn(1) = eqn(3)

[7 + √(49 - 4k)]/2 = [7 - √(49 - 4k)]/2 + 1

7/2 + (√(49 - 4k))/2 = 7/2 - (√(49 - 4k))/2 + 1

collect like terms,

(√(49 - 4k))/2 + (√(49 - 4k))/2 = 7/2 - 7/2 + 1

(√(49 - 4k))/2 + (√(49 - 4k))/2 = 0 + 1

(√(49 - 4k))/2 + (√(49 - 4k))/2 = 1

multiply through by 2

√(49 - 4k) + √(49 - 4k) = 2

2√(49 - 4k) = 2

divide both side by 2

√(49 - 4k) = 1

square both sides

49 - 4k = 1

collect like terms,

4k = 49 - 1

4k = 48

divide both sides by 4

k = 48/4

k = 12

6 0
3 years ago
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3 years ago
Read 2 more answers
40-9x+4x+5 with combining like terms
amid [387]

Answer:

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4 0
3 years ago
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ehidna [41]

9514 1404 393

Answer:

  -12

Step-by-step explanation:

The average rate of change of a function f(x) on an interval [a, b] is defined as ...

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For the given function and interval, this is ...

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The calculator results for f(1.25) and f(0.75) are shown in the attachment, along with the computation of the average rate of change.

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