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3 years ago

Solve the linear equation 2.25 – 11j – 7.75 + 1.5j = 0.5j – 1.

Mathematics

2 answers:

Citrus2011 [14]3 years ago

8 0

Answer:

Option (a) is correct.

2.25 – 11j – 7.75 + 1.5j = 0.5j – 1 simplifies to j = -0.45

Step-by-step explanation:

Given : The linear equation 2.25 – 11j – 7.75 + 1.5j = 0.5j – 1.

We have to solve the given linear equation.

Consider the given linear equation 2.25 – 11j – 7.75 + 1.5j = 0.5j – 1.

Subtract 0.5j both side, we have,

2.25 – 11j – 7.75 + 1.5j - 0.5j = 0.5j – 1 - 0.5j

Simplify, we have,

2.25 – 11j – 7.75 + 1.5j - 0.5j = -1

Adding like terms, we have,

-5.5 -10j = -1

Adding 5.5 both side, we have,

-10j = -1 + 5.5

-10j = 4.5

Divide both side by -10, we have,

j = -0.45

Thus, 2.25 – 11j – 7.75 + 1.5j = 0.5j – 1 simplifies to j = -0.45

disa [49]3 years ago

3 0

The correct answer is:
j= -0.45

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Answer:

$f''(x)=36x^2+4$

Step-by-step explanation:

Let's start by finding the first derivative of $f(x)= 3x^4+2x^2-8x+4$ . We can do so by using the power rule for derivatives.

The power rule states that:

$\frac{d}{dx} (x^n) = n \times x^n^-^1$

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

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Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)$

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$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)$
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