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yKpoI14uk [10]
3 years ago
12

BRAINLIESTTT ASAP!! PLEASE HELP ME :)

Mathematics
1 answer:
Lostsunrise [7]3 years ago
5 0

Answer:

See below  

Step-by-step explanation:

(a) Field lines

A negatively charged particle has an electric field associated with it.

The field lines spread out radially from the centre of the point. They are represented by arrows pointing in the direction that a positive charge would move if it were in the field.

Opposite charges attract, so the field lines point toward the centre of the particle.

For an isolated negative particle, the field lines would look like those in Figure 1 below.

If two negative charges are near each other, as in Figure 2, the field lines still point to the centre of charge.

A positive charge approaching from the left is attracted to both charges, but it moves to the closer particle on the left.

We can make a similar statement about appositive charge approaching from the left.

Thus, there are few field lines in the region between the two particles.

(b) Coulomb's Law

The formula for Coulomb's law is

F = (kq₁q₂)/r²

It shows that the force varies inversely as the square of the distance between the charges.

Thus, the force between the charges decreases rapidly as they move further apart.

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Read 2 more answers
PLEASE HURRY :,) WILL GIVE BRAINLEST
Vlad1618 [11]

Answer:

Point R is at (-40,30),  a distance of 60 units from point Q

Step-by-step explanation:

<u>Explanation </u>

<u>we will use below conditions</u>

<u>Type of transformation</u>                                 <u> change to co-ordinate point</u>

  1. vertical translation up 'd' units                (x, y) changes to (x, y +d)
  2. vertical translation down 'd' units            (x, y) changes to (x, y-d)
  3. horizontal translation left 'c' units            (x, y)  changes to (x- c, y)  

   4. horizontal translation right 'c' units         (x, y) changes to (x+ c , y)

now Given data is P( 20,-30) and in the graph Q(-40,-30)

Step1:-

<u>Now we have to find 'R' point</u>

Given data the point "R' is vertically above point Q so the point "Q' is moves vertically up with '60' units

now we will use the condition (1)

Q(-40,-30) is <u>vertical translation up '60' units </u>now changes the co-ordinate point is (-40 , -30+60)

<u>The correct translation and The point R( -40 , 30)</u>

<u>Step2:-</u>

Again in the given data  "R" is at the same distance from point Q as point P is from point Q.

<u>so given P point is (20 , -30)</u>

now we translation 'P' also

<u>vertically translation up at a distance '60' units</u> and changes the new co-ordinate (20 , -30+60) that is (20,30)  [ use above condition  is (1)]

and again<u> horizontal translation left '60</u>' now changes (20 - 60 ,30)[ use condition (3)]

There fore the new co-ordinate is R( -40 , 30)

<u>Final answer:-</u>

Point R is at (−40, 30), a distance of 60 units from point Q

6 0
3 years ago
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