Most quadratic functions(which is what you have there, to a degree of 2) are solved using factoring and the zero product law. If you can not factor then you have to use the quadratic formula or graph it. However this one can be factored.
It's pretty simple to just factor it by inspection but I use the chart method, if you know decomposition that works as well.
Factoring gives us,

Then you set each factor to 0 and solve for x,



And the second one,


The solutions to this equation are
x = -1/2, 3
Answer:
x = 38
∠P = 26º
Step-by-step explanation:
The sum of the angle in a triangle is 180
x + (x + 78) + (x - 12) = 180
Combine like terms
3x + 66 = 180
Subtract 66 from both sides
3x = 114
Divide both sides by 3
x = 38
-----------------------
∠P = x - 12
∠P = 38 - 12
∠P = 26º
For this case we have the following equation:
V = I * R
Where,
V: voltage
I: current
R: resistance
By clearing R we have:
R = V / I
Substituting the values:
R = (20) / (0.57)
R = 35.09 Ohms
Answer:
The resistance of the light bulb is:
R = 35.09 Ohms
Answer:
y=-1 : )
Step-by-step explanation:
(Brainliest Please)