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klasskru [66]
3 years ago
8

Given that a=3, b=-2 and c= -4, evaluate the following expression. 2c-a/3c+b - 5a+4c/c-a

Mathematics
1 answer:
andrew-mc [135]3 years ago
5 0

Given:

Consider the given expression is:

\dfrac{2c-a}{3c+b}-\dfrac{5a+4c}{c-a}

To find:

The value of the given expression for a=3, b=-2, c=-4.

Solution:

We have,

\dfrac{2c-a}{3c+b}-\dfrac{5a+4c}{c-a}

Substituting a=3, b=-2, c=-4, we get

\dfrac{2(-4)-(3)}{3(-4)+(-2)}-\dfrac{5(3)+4(-4)}{(-4)-(3)}

=\dfrac{-8-3}{-12-2}-\dfrac{15-16}{-4-3}

=\dfrac{-11}{-14}-\dfrac{-1}{-7}

=\dfrac{11}{14}-\dfrac{1}{7}

Taking LCM, we get

=\dfrac{11-2}{14}

=\dfrac{9}{14}

Therefore, the value of the given expression for a=3, b=-2, c=-4 is \dfrac{9}{14}.

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kodGreya [7K]

Given:-   r(t)=< at^2+1,t>  ; -\infty < t< \infty , where a is any positive real number.

Consider the helix parabolic equation :  

                                              r(t)=< at^2+1,t>

now, take the derivatives we get;

                                            r{}'(t)=

As, we know that two vectors are orthogonal if their dot product is zero.

Here,  r(t) and r{}'(t)  are orthogonal i.e,   r\cdot r{}'=0

Therefore, we have ,

                                  < at^2+1,t>\cdot < 2at,1>=0

< at^2+1,t>\cdot < 2at,1>=

                                              =2a^2t^3+2at+t

2a^2t^3+2at+t=0

take t common in above equation we get,

t\cdot \left (2a^2t^2+2a+1\right )=0

⇒t=0 or 2a^2t^2+2a+1=0

To find the solution for t;

take 2a^2t^2+2a+1=0

The numberD = b^2 -4ac determined from the coefficients of the equation ax^2 + bx + c = 0.

The determinant D=0-4(2a^2)(2a+1)=-8a^2\cdot(2a+1)

Since, for any positive value of a determinant is negative.

Therefore, there is no solution.

The only solution, we have t=0.

Hence, we have only one points on the parabola  r(t)=< at^2+1,t> i.e <1,0>




                                               




6 0
3 years ago
Given that justin is collecting data on reaction time, what type of data is he working with?.
Softa [21]

Answer:

Given that Justin is collecting data on reaction time, what type of data is he working with? Reaction time is continuous quantitative data because it is obtained by measuring and is not limited to a certain set of numbers.

8 0
2 years ago
Geometry question. please help ​
Vinvika [58]

Answer:

The length of PQ is <u>18</u> feet.

The length of PR is <u>18</u> feet.

The length of QR is <u>24</u> feet.

Step-by-step explanation:

A way to set an equation up for this problem is:

\frac{4}{3}x+x+x=60

where x is the three lengths of the isosceles triangle, but the base QR is 4/3 the length of the other two congruent sides, length PQ and PR. The 60 represents the total length of the perimeter.

Then, solve for x from the equation, and you’ll get x=18. But your not done yet. Since the variable x in the equation stands for the sides of the isosceles triangle, so plug 18 into the equation and it should look like this:

\frac{4}{3}(18)+18+18=60

Don’t solve the whole equation, just solve the \frac{4}{3}(18) part of the equation, which is equal to 24. So the final equation is this:

24+18+18=60

Conclusion: 24 is the length of QR, and 18 is the length of PQ and PR. And they all equal 60, which is the perimeter. This is very true because the length of PQ and PR are the same (length 18), since it’s an isosceles triangle, and the length of QR is 4/3 the length of PQ and PR (4/3 of 18= 24).

Sorry for the long explanation.

But hope this helps and answers your question :)

8 0
3 years ago
How to find angle measurements of a triangle when given equations?
krek1111 [17]
This is an example
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8 0
3 years ago
Estimate each percent. <br> 26% of 125
kari74 [83]
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3 0
3 years ago
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