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klasskru [66]
3 years ago
8

Given that a=3, b=-2 and c= -4, evaluate the following expression. 2c-a/3c+b - 5a+4c/c-a

Mathematics
1 answer:
andrew-mc [135]3 years ago
5 0

Given:

Consider the given expression is:

\dfrac{2c-a}{3c+b}-\dfrac{5a+4c}{c-a}

To find:

The value of the given expression for a=3, b=-2, c=-4.

Solution:

We have,

\dfrac{2c-a}{3c+b}-\dfrac{5a+4c}{c-a}

Substituting a=3, b=-2, c=-4, we get

\dfrac{2(-4)-(3)}{3(-4)+(-2)}-\dfrac{5(3)+4(-4)}{(-4)-(3)}

=\dfrac{-8-3}{-12-2}-\dfrac{15-16}{-4-3}

=\dfrac{-11}{-14}-\dfrac{-1}{-7}

=\dfrac{11}{14}-\dfrac{1}{7}

Taking LCM, we get

=\dfrac{11-2}{14}

=\dfrac{9}{14}

Therefore, the value of the given expression for a=3, b=-2, c=-4 is \dfrac{9}{14}.

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V + 9<br> ---------- = 8 <br> 3<br><br> Can someone help me ??
bagirrra123 [75]
\frac{v + 9}{3} = 8

Multiply both sides by 3, because 3 is our denominator (bottom number in a fraction), and we want to get rid of the denominator.

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