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jenyasd209 [6]
2 years ago
9

What’s 2-4 plz helppppp

Mathematics
2 answers:
vivado [14]2 years ago
8 0

Answer:

2.A   3.D     4.A

Step-by-step explanation:

You may want to check number four because I'm not sure. Radius is any length from the center of the circle to the edge of the circle. A sector is a piece of a circle, like a cut slice of pie or a slice of pizza.

VladimirAG [237]2 years ago
5 0

Answer:

2. A

3. B

4. A

Step-by-step explanation:

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I need help what is 1/3x-3?​
lilavasa [31]

Answer:

\frac{1}{3}x-3=\frac{x}{3}-3

Step-by-step explanation:

\frac{1}{3}x-3\\\\\frac{1}{3}x = \frac{x}{3}  \\\\Find\:L.C.M.\\\\=\frac{x}{3}-3

8 0
3 years ago
Prove that 3:8 is equivalent to 12:32
Julli [10]
3 times 4 is equal to 12
8 times 4 is equal to 32
therefore 3:8 is equal to 12:32
hope this helps
3 0
2 years ago
Turn 0.272727... into a fraction
kherson [118]

Answer:

0.272727… = 27/99

Step-by-step explanation:

(since 27 is the repeating part of the decimal and it contains 2 digits). We can reduce this fraction (a process that we'll talk more about in a future article) by noticing that we can divide both the numerator and denominator by 9 to get 0.272727… = 27/99 = 3/11.

8 0
2 years ago
Read 2 more answers
I need help with this question I would be grateful really
andreyandreev [35.5K]

Answer:

B

Step-by-step explanation:

B

the vertex is (-5,-2) which eliminates A and C. D says that the x intercepts are both positive which is obviously incorrect making B the correct answer

6 0
3 years ago
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
3 years ago
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