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3 years ago

What is the equation in point-slope form for the line parallel to y=-8x - 5 that contains j(-2, 9)

Mathematics

1 answer:

Julli [10]3 years ago

5 0

Answer:

y - 9 = -8(x + 2)

Step-by-step explanation:

What is the equation in point-slope form for the line parallel to y=-8x - 5 that contains j(-2, 9)

Step 1

y intercept =

y = mx + b

y=-8x - 5

m = -8, b = -5

Point slope form

y - y1 =m( x - x1)

We are given coordinates:

j(-2, 9) = (x1, y1) where ,

x1 = -2

y1 = 9

Hence, our point slope form equation is:

y - 9 = -8(x -(-2))

y - 9 = -8(x + 2)

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