Y = 5x + 30 is the equation
Given:
r = radius = 4
h = height = 12
dr = error in radius = 0.2
What we want to find
dV = error in volume
Use the derivative to find the differential dV
V = pi*r^2*h
dV/dr = d/dr[ pi*r^2*h ]
dV/dr = 2pi*r*h
dV = 2pi*r*h*dr
dV = 2pi*4*12*0.2
dV = 19.2pi
So if the error in measuring the radius is +-0.2 inches, then the error in the cylinder volume is +-19.2pi cubic inches (we either measure the volume to be 19.2pi cubic inches too big, or 19.2pi cubic inches too small)
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Final Answer: Plus or minus 19.2pi cubic inches
Note: your teacher may want you to drop the "plus or minus" part
Answer:
77 = 1 x 77 or 7 x 11.
Step-by-step explanation:
Answer:
x<4 or x>5
Step-by-step explanation:
Answer:
The length of side JK is 4.7 units.
Step-by-step explanation:
Given:
Δ JKL is an Isosceles Triangle.
JL = 5x - 0.2
KL = x + 3.2
JK = 4x - 1.3
To Find:
The length of side JK = ?
Solution:
Δ JKL is an Isosceles Triangle. ......Given
JK = KL .........................Given
Substituting the given values we get

Now substituting 'x' in JK we get

The length of side JK is 4.7 units.