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3 years ago

Can some one please help me with this? I will mark brainlist if right.

Mathematics

1 answer:

pochemuha3 years ago

6 0

Step-by-step explanation:

28<18-5(-3)= 28<33 T

28<18-5(-2)= 28<28 F

28<18-5(-1)= 28< 23 F

28<18-5(0)= 28<18 F

28<18-5(2)= 28<8 F

-3(14)/-51<1 =0.82<1 T

-3(15)/-51<1=0.88<1 T

-3(17)/-51<1=1<1 F

-3(18)/-51<1= 1.1<1 F

-3(19)/-51<1=1.1<1 F

-3,14,15

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Aleonysh [2.5K]

Answer:

A. $y=3x-10$

C. $y+6=3(x-15)$

Step-by-step explanation:

Given:

The given line is $6x+18y=5$

Express this in slope-intercept form $y=mx+b$ , where m is the slope and b is the y-intercept.

$6x+18y=5\\18y=-6x+5\\y=-\frac{6}{18}x+\frac{5}{18}\\y=-\frac{1}{3}x+\frac{5}{18}$

Therefore, the slope of the line is $m=-\frac{1}{3}$ .

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Let us find the slopes of each lines.

Option A:

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On comparing with the slope-intercept form, we get slope as $m_{A}=3$ .

Now, $m\times m_{A}=-\frac{1}{3}\times 3=-1$ . So, option A is perpendicular to the given line.

Option B:

For lines of the form $x=a$ , where, a is a constant, the slope is undefined. So, option B is incorrect.

Option C:

On comparing with the slope-point form, we get slope as $m_{C}=3$ .

Now, $m\times m_{C}=-\frac{1}{3}\times 3=-1$ . So, option C is perpendicular to the given line.

Option D:

$3x+9y=8\\9y=-3x+8\\y=-\frac{3}{9}x+\frac{8}{9}\\y=-\frac{1}{3}x+\frac{8}{9}$

On comparing with the slope-intercept form, we get slope as $m_{D}=-\frac{1}{3}$ .

Now, $m\times m_{D}=-\frac{1}{3}\times -\frac{1}{3}=\frac{1}{9}$ . So, option D is not perpendicular to the given line.

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