Answer:6
Step-by-step explanation:
*we solve every bracket alone
-(√2+1)² = [rule:1st *1st + 2*1st*2nd + 2nd*2nd]
2+2√2+1
3+2√2
-(√2-1)= [rule:1st*1st - 2*1st*2nd + 2nd+2nd]
2-2√2+1
3-2√2
-we write the whole equation
3+2√2+3-2√2 (+2√2 - 2√2) {positive and negative remove each other}
3+3=6
Answer: YES
Step-by-step explanation: A polygon which has all its sides of equal length and all its angles of equal measures is called a regular polygon. ... Therefore, a regular pentagon is a regular polygon. Irregular polygon: A polygon which has all its sides of unequal length and all its angles of unequal measures is called an irregular polygon.
<span>x : y is equal to 12 : 8. These can be reduced or cancelled down to 3 : 2 in the same proportions. Therefore, when y is 12, you have to multiply the smallest value y can be by 6, and must do the same to the smallest x value to retain the proportions. x = 18 when y = 12.</span>
Answer:
-7
Step-by-step explanation:
You use the quadratic formula of 
to get:
a = 1
b = 7
c = -13
then you plug that into x= (-b ± √b²-4ac)/(2a) :
x= ( -7 ± √7²- 4(1)(-13) )/(2(1))
The sum of these two x values turns out to be:
Answer:
5r^2+2
Step-by-step explanation:
(4r^2 – 3r + 2) – (-r^2 – 3r) =
Distribute the minus sign
(4r^2 – 3r + 2) +r^2 + 3r =
Combine like terms
(4r^2 + r^2 – 3r+ 3r + 2) =
5r^2+2
