8n+4 because you have to add it all up
Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.

Multiply both sides by 100.


Divide both sides by 50.


The amount invested at 7% is
.
The amount invested at 8% is

The amount invested at 9% is

Thus, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.
Answer:
$345 : whichever is closest
Step-by-step explanation:
Pants were $20 each and she bought 9 of them so multiply:
9x20=180
She paid $180 for 9 pants.
Shirts cost $15 each and she bought 11 of them so Mulitply:
15x11=165
She paid $165 for 11 shirts
Add both totals from pants and shirts
165+180=$345
ANSWER

EXPLANATION
From the Pascal's triangle,
The coefficients are :
1, 5, 10,10, 5,1
Because of the negative sign, the expansion will alternate sign.

We now put y=5 into the expansion to get,

