The difference between the cups of sugar is 1/6, hence you have enough sugar.
<h3>Difference and sum of fractions</h3>
Fractions are written as a ratio of two integers, For instance, a/b is a fraction where a and b are integers.
According to the question, a recipe calls for 2 1/2 cups of sugar. If have 2 2/3 cups of sugar;
Difference of cups of sugar = 2 2/3 - 2 1/2
Convert to improper fraction
Difference = 8/3 - 5/2
Difference = 16-15/6
Difference = 1/6
Since the difference between the cups of sugar is 1/6, hence you have enough sugar.
Learn more on fraction here: brainly.com/question/17220365
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The shape of the water is that of a "spherical cap." The formula for the volume of a spherical cap is ...
... V = π·h²·(r -h/3) . . . . . . . from web search
For a radius of 5 in, this is
... V = π·h²·(5 -h/3) . . . . in³
_____
For h=0
... V = π·0²·(5 -0/3) = 0
For h=5 in
... V = π·(5 in)²·((5 -5/3) in) = (2/3)π·5³ in³ . . . . . the volume of a hemisphere of radius 5
Answer:
a. 
b. 
Step-by-step explanation:
First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

The rate is negative as it represents the amount of caffeine leaving the body at certain time.
Answer:
B and C
Step-by-step explanation: