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3 years ago

Solve the inequality

Mathematics

1 answer:

iren2701 [21]3 years ago

3 0

Answer:

A- v<7/12

Step-by-step explanation:

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Select true or false for the statements

jok3333 [9.3K]

Answer: First Question: True

Second Question: False

Third Question: False

Step-by-step explanation:

Based on the equations in the image, I used the substitution method.

4 0

3 years ago

(0.49+0.045)÷5 show steps to solve this

Rzqust [24]

Solve within parenthesis first so .49 +.045 =.535 so then divide by five which is .107

4 0

3 years ago

Read 2 more answers

How to differentiate y=x^n using the first principle. In this question, I cannot use the rule of differentiation. I have to do t

Zarrin [17]

By first principles, the derivative is

$\displaystyle\lim_{h\to0}\frac{(x+h)^n-x^n}h$

Use the binomial theorem to expand the numerator:

$(x+h)^n=\displaystyle\sum_{i=0}^n\binom nix^{n-i}h^i=\binom n0x^n+\binom n1x^{n-1}h+\cdots+\binom nnh^n$

$(x+h)^n=x^n+nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n$

where

$\dbinom nk=\dfrac{n!}{k!(n-k)!}$

The first term is eliminated, and the limit is

$\displaystyle\lim_{h\to0}\frac{nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n}h$

A power of $h$ in every term of the numerator cancels with $h$ in the denominator:

$\displaystyle\lim_{h\to0}\left(nx^{n-1}+\dfrac{n(n-1)}2x^{n-2}h+\cdots+nxh^{n-2}+h^{n-1}\right)$

Finally, each term containing $h$ approaches 0 as $h\to0$ , and the derivative is

$y=x^n\implies y'=nx^{n-1}$

4 0

3 years ago

Find the measure of angle y. Round your answer to the nearest hundredth. (please type the numerical answer only) (6 points) A ri

Harlamova29_29 [7]

Answer:y= 19.65

Step-by-step explanation:

i took the test

4 0

3 years ago

Read 2 more answers

What is the slope of the line passing through the points (7, 10) and (5, 16) ?<br> Thank you

butalik [34]

Answer:

m=-3

Step-by-step explanation:

m=y2-y1/x2-x1

m=16-10/5-7

m=6/-2

m=-3

4 0

2 years ago