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KonstantinChe [14]

3 years ago

12

A boat went downstream and traveled a distance in 3 hours. the return took 3 hours and 40 min. find the speed of the water curre

nt of the speed of the boat in still water is 18

1 answer:

Katen [24]3 years ago

7 0

Answer:

Step-by-step explanation

:

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Does anybody play Ro,blox???

poizon [28]

Answer:

i do! can i have brainliest? please? ill give you my thanks

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Please help & explain!!!!!!!

Naily [24]

F(-3) means x = -3

Look at the functions above, if x <= - 3 then use F(x) = 7 - x

so
F(-3) = 7 - x, replace x = - 3 into the function
F(-3) = 7 - (-3)
F(-3) = 7 + 3
F(-3) = 10

7 0

3 years ago

A store is having a sale on walnuts and chocolate chips. For 2 pounds of walnuts and 12 pounds of chocolate chips, the total cos

gladu [14]

The total cost of pound of walnut and a pound of chocolate together is $4

Step-by-step explanation:

Let us assume the cost of walnut as $w per pound

Similarly, let us assume the cost of chocolate at $c per pound

Putting the above assumptions in the given conditions mentioned in the question-

Condition 1- the cost of 2-pound walnut and 12-pound chocolate is $ 33

The 2-pound walnut cost can be written as 2w (since we have assumed that walnut cost $w/pound)

Similarly, 12-pound chocolate would cost 12c

2w+12c=33 Equation 1

Condition 2- the cost of 5-pound walnut and 3-pound chocolate is $15

5-pound walnut cost 5w and 3-pound chocolate cost 3c which equals $15

5w+3c=15 Equation 2

Comparing Equation 1 and Equation 2

We multiply Equation 2 with a factor of 4

Hence the equation 2 becomes- 20w+12c=60 (this was done to make either of the variable’s coefficient equal)

Now subtracting Equation 1 from Equation 2

20w+12c=60 -(2w+ 12c=33)

We get 20w-2w=60-33 (12c gets cancelled out)

18w=27

w=$ 1.5 (cost of walnut is $1.5/pound)

putting the value of w in either of the equation we get c as 2.5$

Hence the total cost of one pound each of walnut and chocolate is $2.5+$1.5= $4

8 0

3 years ago

What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6

RoseWind [281]

Answer: $\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

$a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0$

Where:

- The coefficients are integers.

- $a_n$ is the leading coeffcient ( $a_n\neq 0$ )

- $a_0$ is the constant term $a_0\neq 0$

Every rational root of the polynomial is in the form:

$\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}$

For the case of the given polynomial:

$2x^7+3x^5-9x^2+6=0$

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

Then, by Rational Roots Test we get the possible rational roots of this polynomial:

$\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

5 0

3 years ago

Pleeeeaaaseee help!!

PSYCHO15rus [73]

Answer:

Step-by-step explanation:

The equation is 3x - 5y =20.

Suppose we start with (5, y). What value of y is a solution of this equation?

Substitute 5 for x in 3x - 5y =20, obtaining: 3(5) - 5y = 20.

Then -5y = 5, and y = -1. Thus, (5, -1) is a solution of 3x - 5y =20.

Next:

We have (x, 2). Find the value of x that makes (x, 2) a solution of 3x - 5y =20.

Replace y with 2: 3x - 5(2) =20

Then 3x = 30, and x = 10. So (10, 2) is a solution of 3x - 5y =20.

3 0

4 years ago