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Troyanec [42]
3 years ago
9

Can someone please help mee

Mathematics
1 answer:
creativ13 [48]3 years ago
3 0
1. slope
2. x-axis
3. y-axis
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Solve 0=x2+6x+13 by completing the square.
Alinara [238K]

Answer:

x=-x+2i

x=-x-2i

Step-by-step explanation:

4 0
3 years ago
When given a word problem, what should you always do to better visualize the problem?
Aliun [14]

Step-by-step explanation:

1.Read the Entire Word Problem.

2.Think About the Word Problem.

3.Write on the Word Problem.

4.Draw a Simple Picture and Label It.

5.Estimate the Answer Before Solving.

6.Check Your Work When Done.

7.Practice Word Problems Often.

7 0
3 years ago
Please help! and thank you so much!
mel-nik [20]

Answer:

  (d)  30 units²

Step-by-step explanation:

The area of the rectangle is the product of the length and width. It is equal to the number of unit squares that fill the rectangle.

__

By counting grid squares or subtracting coordinates, we can see this rectangle is 3 units wide and 10 units high. Its area will be ...

  A = WH

  A = (3 units)(10 units) = 30 units²

_____

<em>Additional comment</em>

You can also count the three columns of 10 shaded squares, or the 10 rows of 3 shaded squares. Either way, you will count 30 square units covering the rectangle.

8 0
2 years ago
A rectangle has a perimeter of 30 feet and an area of 50 square feet. What are the dimensions of the rectangle?
REY [17]
Perimeter (p) = 2×length (l) + 2×width (w)
p = 2l+2w
area (a) = l×w, so solve for one (I'll use l):
a = l \times w \\ l =  a \div w \\ p = 2l + 2w = 2(l + w)
since p = 30, and a = 50, substitute the "a÷w" in for l in the perimeter equation:
p = 2(l + w) = 2((a \div w) + w) \\  = 2((a \div w) + ( {w}^{2} \div w)) \\  p= 2((a +  {w}^{2}) \div w
Now plug in p and a values:
p= 2((a +  {w}^{2}) \div w) \\ 30 = 2((50 +  {w}^{2}) \div w)  \\ 30 \div 2 = (50 +  {w}^{2}) \div w \\ 15w = 50 +  {w}^{2}
15w = 50 +  {w}^{2}  \\  {w}^{2}  - 15w + 50 = 0 \\ (w - 5)(w - 10) = 0
therefore width can be either 5 or 10 (but not both), so let's plug in:
l = a÷w = 50÷5 = 10
So if w = 5, then l = 10

D) 5 feet, and 10 feet
3 0
3 years ago
at 10a.m. you consume an energy drink containing 800mg of caffeine. if the half-life of caffeine is 5.7 hours, how much caffeine
icang [17]

Answer:

268 mg

Step-by-step explanation:

Let A₀ = the original amount of caffeine

The amount remaining after one half-life is ½A₀.

After two half-lives, the amount remaining is ½ ×½A₀ = (½)²A₀.

After three half-lives, the amount remaining is ½ ×(½)²A₀ = (½)³A₀.

We can write a general formula for the amount remaining:

A =A₀(½)ⁿ

where n is the number of half-lives .

n = t/t_½

Data:

  A₀ = 800 mg

    t₁ = 10 a.m.

   t₂ = 7 p.m.  

t_½ = 5.7 h

Calculations:

(a) Calculate t

t = t₂ - t₁ = 7 p.m. - 10 a.m. = 19:00 - 10:00 = 9:00 = 9.00 h

(b) Calculate n

n = 9.00/5.7 = 1.58

(b) Calculate A

A = 800 × (½)^1.58 = 800 × 0.334 = 268 mg

You will still have 268 mg of caffeine in your body at 10 p.m.

6 0
3 years ago
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