Answer:
y=6
Step-by-step explanation:
edge2020
Step-by-step explanation:
Y= x - 2. Y = 3x + 5
Putting value of y
x - 2 = 3x + 5
-2 - 5 = 3x - x
-7 = 2x
-7/2 = x
Putting value of x
Y = 3(-7/2) + 5
Y = - 10.5 + 5
Y = - 5.5
Answer:
1. No.

Since f(1)=f(3) and
then f isn't one-to-one.
2. No

Since f(0)=f(2) and
then f isn't one-to-one.
3. No

Since f(0)=f(2) and
then f isn't one-to-one.
4. Yes

Since
, then f is one-to-one
5. Since f(1)=f(3) and
then, f isn't one-to-one
Answer:
0.4996
Step-by-step explanation:
We are given;
Population proportion; p = 14% = 0.14
Sample size; n = 804
Sample proportion; p^ = 13% = 0.13
Standard deviation; σ = √np(1 - p)
σ = √(804 × 0.14 × (1 - 0.14))
σ = 9.8388
Formula for z-score is;
z = (p^ - p)/σ
z = (0.13 - 0.14)/9.8388
z = -0.01/9.8388
z = -0.001
From online z-score and probability converter attached, we have;
P(Z < -0.001) = 0.4996