Answer:
5! or 120.
Step-by-step explanation:
Think about this logically:
You have 5 players to start off with, so you have 5 players that can go in the first position.
That leaves you with 4 players. Any one of those 4 players can go in the second position.
And then there were 3 players. Any one of those 3 players can go in the third position.
2 to go! Pick your favorite player out of the 2 available to go in the fourth position.
And that leaves just one player who has to go last.
This can be modeled as: 5x4x3x2x1, or 5!, which equals 120 unique permutations.