Brenna writes a product of six negative factors. She uses the following steps to determine that the product of the six numbers w
ill be positive. Step 3 is missing. Group the factors into pairs.
The numbers in each pair have the same sign.
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The product of three positive numbers is positive.
Therefore, the product of the original six factors is positive.
What is step 3?
A. The product of two numbers with the same sign is positive.
B. The product of two numbers with different signs is negative.
C. The factors in a product can be grouped in any way without changing the value of the product.
D. The factors in a product can be written in any order without changing the value of the product.
Porobability distribution of X x P(x) 0 0.2 1 0.4 2 0.4 Total .1.0 i] Expectation Mean=Σxp Variance=x²p-(∑xp)² thus: Mean=(0*0.2)+(1*0.4)+(2*0.4) =0+0.4+0.8 =1.2
ii] Variance Variance=[(0²*0.2)+(1²*0.4)+(2²*0.4)]-(1.2)² =[0+0.4+1.6]-1.44 =0.56 hence: standard deviation=sqrt(0.56)=0.74833
