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Hoochie [10]
3 years ago
11

Brenna writes a product of six negative factors. She uses the following steps to determine that the product of the six numbers w

ill be positive. Step 3 is missing.
Group the factors into pairs.
The numbers in each pair have the same sign.
_____________________________________
The product of three positive numbers is positive.
Therefore, the product of the original six factors is positive.

What is step 3?
A. The product of two numbers with the same sign is positive.
B. The product of two numbers with different signs is negative.
C. The factors in a product can be grouped in any way without changing the value of the product.
D. The factors in a product can be written in any order without changing the value of the product.
Mathematics
2 answers:
SIZIF [17.4K]3 years ago
5 0
The answer is A because you have to think about the positives and not letting the negative in the numbers. Stay safe c: you
Orlov [11]3 years ago
4 0

Answer:

A

Step-by-step explanation:

The product of two numbers with the same sign is positive.

Since the numbers in each pair have the same sign, the product will be positive.

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Help ! solve the following system of equations <br><br> -9x+2y=-13<br><br> 2x-9y=20
Stella [2.4K]

Answer: x = 1, y = -2

Step-by-step explanation:

-9x+2y=-13

x= 13/9 + 2/9y

2x-9y=20

2(13/9+2/9y)-9y=20

<em>Substitute y with -2.</em>

<em />

x= 13/9+2/9(-2)

<em>After solving you'll see that 1 is a possible solution for x.</em>

<em />

Check your answer

-9x+2y=-13

-9x1+2(-2) = -13

2x-9y=20

2x1-9(-2) = 20

-13 = -13

20 = 20

Therefore, x=1 and y=-2

5 0
3 years ago
A person recently read that 84% of cat owners are women. How large a sample should the researcher take if she wishes to be 90% c
Lana71 [14]

Answer:

405

Step-by-step explanation:

To find sample size, use the following equation, where n = sample size, za/2 = the critical value, p = probability of success, q = probability of failure, and E = margin of error.

n=\frac{(z_{\frac{\alpha }{2} })^{2} *p*q  }{E^2}

The values that are given are p = 0.84 and E = 0.03.

You can solve for the critical value which is equal to the z-score of  (1 - confidence level)/2.  Use the calculator function of invNorm to find the z-score.  The value will given with a negative sign, but you can ignore that.

(1 - 0.9) = 0.1/2 = 0.05

invNorm(0.05, 0, 1) = 1.645

You can also solve for q which is 1 - p.  For this problem q = 1 - 0.84 = 0.16

Plug the values into the equation and solve for n.

n =\frac{(1.645)^2*0.84*0.16}{(0.03)^2}\\n= 404.0997333

Round up to the next number, giving you 405.

6 0
3 years ago
Evaluate 3x+6y when x= -3, y=6
sesenic [268]

Hey there!!!

Given equation - 3x+6y

x is given as -3

y is given as 6

Plugin these values to get the final answer

3 ( -3 ) + 6 ( 6 )

-9 + 36

= 27

27 is the final and the required answer

Hope my answer helps!

3 0
3 years ago
Read 2 more answers
Enny White is shopping for CDs. She decides to purchase 3 movie soundtracks. The music store has 7 different movie soundtracks i
zubka84 [21]

Answer:

35\ ways

Step-by-step explanation:

we know that

<u><em>Combinations</em></u> are a way to calculate the total outcomes of an event where order of the outcomes does not matter.

To calculate combinations, we will use the formula

C(n,r)=\frac{n!}{r!(n-r)!}

where

n represents the total number of items

r represents the number of items being chosen at a time.

In this problem

n=7\\r=3

substitute

C(7,3)=\frac{7!}{3!(7-3)!}\\\\C(7,3)=\frac{7!}{3!(4)!}

simplify

C(7,3)=\frac{(7)(6)(5)4!}{3!(4)!}

C(7,3)=\frac{(7)(6)(5)}{3!}

C(7,3)=\frac{(7)(6)(5)}{(3)(2)(1)}

C(7,3)=35\ ways

6 0
3 years ago
sThe number of users on a social networking site was 45 thousand in February when theyofficially went public, and grew to 60 tho
svetoff [14.1K]

Given:

No of users in February is 45,000 and in october its 60,000.

P=45000(\frac{4}{3})^{(\frac{3}{2})^t}

t=2

P=45000(\frac{4}{3})^3P=45000(\frac{64}{27})P=5000(\frac{64}{3})P=106666.6667

Therefore, approximate no of users after 2 years is 106667.

6 0
2 years ago
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