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2 years ago

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There is 3/4 of an apple pie left from dinner, Tomorrow, Victor plans to eat 1/4 of the pie that was left. Enter how much of the

whole pie he will eat tomorrow.

1 answer:

abruzzese [7]2 years ago

3 0

Answer:

2/4??..

Step-by-step explanation:

Please don't really use this answer because it is random

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If Adrianna can read 7 pages in 10 minutes. At this rate, how many page can she read in 25 minutes?

lesya692 [45]

3.5 : 5

7 : 10

14 : 20

17.5 : 25

At that rate, she can read 17.5 pages in 25 minuets.

Divide both 7 and 10 by 2, which gets 3.5 and 5

5 * 5 = 25

5 * 3.5 = 17.5

Therefore, in 25 minuets, she can read 17.5 pages.

4 0

2 years ago

Read 2 more answers

I need help with these questions! My teacher didn’t teach me how to do these-

fgiga [73]

Answer:

Graph A has infinite solutions, Graph B has one solution, and Graph C has no solutions

Step-by-step explanation:

6 0

2 years ago

Pumping stations deliver oil at the rate modeled by the function D, given by d of t equals the quotient of 5 times t and the qua

goblinko [34]

<h2>Hello!</h2>

The answer is: There is a total of 5.797 gallons pumped during the given period.

<h2>Why?</h2>

To solve this equation, we need to integrate the function at the given period (from t=0 to t=4)

The given function is:

$D(t)=\frac{5t}{1+3t}$

So, the integral will be:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dx$

So, integrating we have:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dt=5\int\limits^4_0 {\frac{t}{1+3t}} \ dx$

Performing a change of variable, we have:

$1+t=u\\du=1+3t=3dt\\x=\frac{u-1}{3}$

Then, substituting, we have:

$\frac{5}{3}*\frac{1}{3}\int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du\\\\\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u}{u} -\frac{1}{u } \ du$

$\frac{5}{9} \int\limits^4_0 {(\frac{u}{u} -\frac{1}{u } )\ du=\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u } )$

$\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u })\ du=\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du$

$\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du=\frac{5}{9} (u-lnu)/[0,4]$

Reverting the change of variable, we have:

$\frac{5}{9} (u-lnu)/[0,4]=\frac{5}{9}((1+3t)-ln(1+3t))/[0,4]$

Then, evaluating we have:

$\frac{5}{9}((1+3t)-ln(1+3t))[0,4]=(\frac{5}{9}((1+3(4)-ln(1+3(4)))-(\frac{5}{9}((1+3(0)-ln(1+3(0)))=\frac{5}{9}(10.435)-\frac{5}{9}(1)=5.797$

So, there is a total of 5.797 gallons pumped during the given period.

Have a nice day!

4 0

3 years ago

M is the midpoint of AD. Triangles A B M and D C M are connected at point M. Sides A B and C D are congruent. The lengths of sid

SVETLANKA909090 [29]

Answer:

<h2>Reflection.</h2>

Step-by-step explanation:

The image attached shows a representation of the problem, there you can observe the congruence between triangles.

Also, using the images you can easily deduct the transformation we need to map one triangle onto the other one, we just need to reflect one triangle across and axis that pass through point M, such line acts like a mirror.

Therefore, the right answer is reflection.

8 0

2 years ago

P is the incenter of QRS. Use the given information to determine find the indicated measure.

never [62]

<span>The incenter is equidistant from all three triangle sides.
So, PJ = PK = PL.
PJ = 4x -8
PL = x + 7

Therefore,
</span>4x -8 = <span>x + 7
3x = 15
x = 5
So, PJ = 12
PL = 12 and
PK = 12

</span>

5 0

3 years ago