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3 years ago

Please help me I don’t know this

Mathematics

1 answer:

Marianna [84]3 years ago

5 0

Answer:

1. 10/21

2. 11/21

Step-by-step explanation:

You might be interested in

Find the product: 377(10, 000).

Illusion [34]

Answer:

37, 700, 000

Step-by-step explanation:

377(10,000) = 377 x 10,000

= 37, 700, 000

an easy way to see it is to just add the number of zeros from 10,000 to 377. since there are four zeros, you put four zeros behind 377.

<em><u>[it's not mathematical but it helps u see the answer better. and it only works with numbers that start with 1]</u></em>

7 0

4 years ago

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

2 years ago

Which figure has two bases and one lateral face that is rectangular?

vodomira [7]

Rectangular pyramid

4 0

3 years ago

Read 2 more answers

Translate each of the following research questions into appropriate H0 and Ha.

Mandarinka [93]

Answer:

$H_{0}: \mu = 62500\text{ dollars per year}\\H_A: \mu > 62500\text{ dollars per year}$

$H_{0}: \mu = 2.6\text{ hours}\\H_A: \mu \neq 2.6\text{ hours}$

Step-by-step explanation:

We have to build appropriate null and alternate hypothesis for the given scenarios.

a) Population mean, μ = $62,500 per year

The market research wants to find whether the mean household income of mall shoppers is higher than that of the general population.

$H_{0}: \mu = 62500\text{ dollars per year}\\H_A: \mu > 62500\text{ dollars per year}$

We would use one-tail(right) test to perform this hypothesis.

b) Population mean, μ = 2.6 hours

The company want to know the average time to respond to trouble calls is different or not.

$H_{0}: \mu = 2.6\text{ hours}\\H_A: \mu \neq 2.6\text{ hours}$

We would use two-tail test to perform this hypothesis.

7 0

3 years ago

Brooke made 10 liters of juice blend that is 60% juice for her brothers birthday party but her mother wants her to make it 80% j

ANEK [815]

The answer is 2 litters of juice

6 0

3 years ago