Answer: I hope this is what you are looking for
Step-by-step explanation:
so the answer is
x=y +v/b
Hey there :)
To find the slope with <em>two points</em> we will need to use the equation ![\frac{y^2-y^1}{x^2-x^1}](https://tex.z-dn.net/?f=%5Cfrac%7By%5E2-y%5E1%7D%7Bx%5E2-x%5E1%7D)
![y^2](https://tex.z-dn.net/?f=y%5E2)
( 3 , -20 ) ( 5 , 8 )
Here is what the equation should look like when replaced with the numbers (<em>it will be a fraction</em>) :
![\frac{8 - (-20)}{5 - 3}](https://tex.z-dn.net/?f=%5Cfrac%7B8%20-%20%28-20%29%7D%7B5%20-%203%7D)
We know that <em>two negatives</em> cancel out and make a positive, so the numerator would actually be 8 + 20.
Solve the fraction and we get ![\frac{28}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B28%7D%7B2%7D)
28 <em>divided</em> by 2 is 14. The slope is 14.
Answer:
![x=-2,0,3](https://tex.z-dn.net/?f=x%3D-2%2C0%2C3)
Step-by-step explanation:
We have been given a function
. We are asked to find the zeros of our given function.
To find the zeros of our given function, we will equate our given function by 0 as shown below:
![15x^3-15x^2-90x=0](https://tex.z-dn.net/?f=15x%5E3-15x%5E2-90x%3D0)
Now, we will factor our equation. We can see that all terms of our equation a common factor that is
.
Upon factoring out
, we will get:
![15x(x^2-x-6)=0](https://tex.z-dn.net/?f=15x%28x%5E2-x-6%29%3D0)
Now, we will split the middle term of our equation into parts, whose sum is
and whose product is
. We know such two numbers are
.
![15x(x^2-3x+2x-6)=0](https://tex.z-dn.net/?f=15x%28x%5E2-3x%2B2x-6%29%3D0)
![15x((x^2-3x)+(2x-6))=0](https://tex.z-dn.net/?f=15x%28%28x%5E2-3x%29%2B%282x-6%29%29%3D0)
![15x(x(x-3)+2(x-3))=0](https://tex.z-dn.net/?f=15x%28x%28x-3%29%2B2%28x-3%29%29%3D0)
![15x(x-3)(x+2)=0](https://tex.z-dn.net/?f=15x%28x-3%29%28x%2B2%29%3D0)
Now, we will use zero product property to find the zeros of our given function.
![15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0](https://tex.z-dn.net/?f=15x%3D0%5Ctext%7B%20%28or%29%20%7D%28x-3%29%3D0%5Ctext%7B%20%28or%29%20%7D%28x%2B2%29%3D0)
![15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0](https://tex.z-dn.net/?f=15x%3D0%5Ctext%7B%20%28or%29%20%7Dx-3%3D0%5Ctext%7B%20%28or%29%20%7Dx%2B2%3D0)
![\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0](https://tex.z-dn.net/?f=%5Cfrac%7B15x%7D%7B15%7D%3D%5Cfrac%7B0%7D%7B15%7D%5Ctext%7B%20%28or%29%20%7Dx-3%3D0%5Ctext%7B%20%28or%29%20%7Dx%2B2%3D0)
![x=0\text{ (or) }x=3\text{ (or) }x=-2](https://tex.z-dn.net/?f=x%3D0%5Ctext%7B%20%28or%29%20%7Dx%3D3%5Ctext%7B%20%28or%29%20%7Dx%3D-2)
Therefore, the zeros of our given function are
.
Answer:
(3, -3) is correct
Step-by-step explanation:
-4 × 3 = -12. -12 + 9 = -3
The slope, or gradient, of the line is 6/-3 which is -2. The gradient is -2.