The 15 lbs at $7=$105
So multiple 5x9 as a test and check results. 105-45=60
Here you can see that 60 is a factor of 6 by 10 so you got lucky and got the answer of 10lbs at $6 & 5lbs at $9=15 lbs at $7 average
36 km
--------- = 12 km/liter
3 lit
Pat can drive 12 km per liter of gas.
Answer:
First number: -39
Second number: -37
Step-by-step explanation:
An odd number can be written as 
where n is a whole number.
Let's call our first number 2n+1.
Our second, consecutive number will be 2 more than our first number, since it has to be odd. All numbers go: odd -> even -> odd -> even. If we have an odd number, and add 2, we'll get the next odd number.
First number: 2n+1
Second number: 2n+1+2 = 2n+3
The sum of these two numbers, 2n+1 and 2n+3 will be -76.
(2n+1) + (2n+3) = -76
2n + 2n + 1 + 3 = -76
4n + 4 = -76
4n = -80
n = -20
Since our first number is 2n+1:
2 * (-20) + 1 = -40 + 1 = -39
First number: -39
Our second number is 2n+3, or 2 more than our first number.
-39 + 2 = -37
Second number: -37
We can double check this:
-39 + (-37) = -39 - 37 = -76
Given that a company budgeted 5 1/4 hours to complete a project, determine how much time they spent on research if they spent 1/3 of the total budget.
First, convert the budget from hours into minutes.
5 1/4 hours = 315 minutes
1 hour = 60 min
1/4 hour = 15 min
60 x 5 = 300
300 + 15 = 315
Then, divide the minutes by 3 or multiply it by 1/3.
315 / 3 = 105
315 x 1/3 = 105
Lastly convert to a mixed number.
1 3/4 hour
Thus, the company plans to spend 1 3/4 hours or 1 hour and 45 minutes on research.
Using binomial distribution where success is the appearing of any of the top 10 most common names, thus probability of success (p) is 9.6% = 0.096 and the probability of failure = 1 - 0.096 = 0.904. Number of trials is 11.
Binomial distribution probability is given by P(x) = nCx (p)^x (q)^(n - x)
Probability that none of the top 10 most common names appears is P(0) = 11C0 (0.096)^0 (0.904)^(11 - 0) = (0.904)^11 = 0.3295
Thus, the probability that at least one of the 10 most common names appear is 1 - 0.3295 = 0.6705
Therefore, I will be supprised that none of the names of the authors were among the 10 most common names given that the probability that at least one of the names appear is 67%.
