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3 years ago

Which ordered pair (x, y) is a solution to given system of linear equations?

Mathematics

2 answers:

Jet001 [13]3 years ago

7 0

Answer: (1,-2)

Step-by-step explanation:

Given : the system of linear equations :-

$3x+y=1---------------(1)\\5x+y = 3---------------(2)$

In order to find x and y , first we subtract equation (1) from equation (2) , we get

$2x=2$

Divide both sides by 2 , we get

$x=1$

Substitute the value of x=1 in equation (1) , we get

$3(1)+y=1\\\\3+y=1$

Subtract 3 from both sides , we get

$y=-2$

Hence, the ordered pair (x, y) is a solution to given system of linear equations = (1,-2)

Thus , the correct answer is (1,-2) .

riadik2000 [5.3K]3 years ago

3 0

Answer:

(1, - 2 )

Step-by-step explanation:

Given the 2 equations

3x + y = 1 → (1)

5x + y = 3 → (2)

Subtracting (1) from (2) term by term eliminates the term in y, that is

(5x - 3x) + (y - y) = (3 - 1) and simplifying

2x = 2 ( divide both sides by 2 )

x = 1

Substitute x = 1 in either of the 2 equations for corresponding value of y

Using (1), then

3 + y = 1 ( subtract 3 from both sides )

y = - 2

Solution is (1, - 2 )

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Woo-Jin and Kiran were asked to find an explicit formula for the sequence 64\,,\,16\,,\,4\,,\,1,...64,16,4,1,...64, comma, 16, c

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Answer:

$f(n)=64(\frac{1}{4})^{n-1}$

Step-by-step explanation:

The given sequence is

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$r_1=\dfrac{a_2}{a_1}=\dfrac{16}{64}=\dfrac{1}{4}$

$r_2=\dfrac{a_3}{a_2}=\dfrac{4}{16}=\dfrac{1}{4}$

$r_3=\dfrac{a_4}{a_3}=\dfrac{1}{4}$

It is a geometric series because it has a common ratio $r_1=r_2=r_3=\dfrac{1}{4}$ .

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3 years ago

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Who answers this correctly with explanation gets vevmo'd/pay pal 25 Any Links Will Be Reported.

Inga [223]

Answer:

the answer is C

hope this helps

have a good day :)

Step-by-step explanation:

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2 years ago

1. Which point on the axis satisfies the inequality y

grigory [225]

Answer:

1) Point $(1,0)$ -----> see the attached figure N $1$

2) The value of x is $4$

3) I quadrant

4) $(1,1)$

5) $y>-5x+3$

Step-by-step explanation:

Part 1)

we know that

If the point satisfy the inequality

then

the point must be included in the shaded area

The point $(1,0)$ is included in the shaded area

Part 2)

we have

$x-2y\geq 4$

see the attached figure N $2$

we know that

The value for x on the boundary line and the x axis is equal to the x-intercept of the line $x-2y= 4$

For $y=0$

Find the value of x

$x-2(0)= 4$

$x=4$

The solution is $x=4$

Part 3)

we have

$x\geq 0$ -----> inequality A

The solution of the inequality A is in the first and fourth quadrant

$y\geq 0$ -----> inequality B

The solution of the inequality B is in the first and second quadrant

the solution of the inequality A and the inequality B is the first quadrant

Part 4) Which ordered pair is a solution of the inequality?

we have

$y\geq 4x-5$

we know that

If a ordered pair is a solution of the inequality

then

the ordered pair must be satisfy the inequality

we're going to verify all the cases

case A) point $(3,4)$

Substitute the value of x and y in the inequality

$x=3,y=4$

$4\geq 4(3)-5$

$4\geq 7$ ------> is not true

therefore

the point $(3,4)$ is not a solution of the inequality

case B) point $(2,1)$

Substitute the value of x and y in the inequality

$x=2,y=1$

$1\geq 4(2)-5$

$1\geq 3$ ------> is not true

therefore

the point $(2,1)$ is not a solution of the inequality

case C) point $(3,0)$

Substitute the value of x and y in the inequality

$x=3,y=0$

$0\geq 4(3)-5$

$0\geq 7$ ------> is not true

therefore

the point $(3,0)$ is not a solution of the inequality

case D) point $(1,1)$

Substitute the value of x and y in the inequality

$x=1,y=1$

$1\geq 4(1)-5$

$1\geq -1$ ------> is true

therefore

the point $(1,1)$ is a solution of the inequality

Part 5) Write an inequality to match the graph

we know that

The equation of the line has a negative slope

The y-intercept is the point $(3,0)$

The x-intercept is a positive number

The solution is the shaded area above the dashed line

the equation of the line is $y=-5x+3$

The inequality is $y>-5x+3$

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