Dana records the heights and the shoe sizes of the girls on her volleyball

How do you determine if the line segments are congruent

Gemiola [76]

You must calculate the length of the segments.

Suppose segments AB and CD
Being A (m, n), B (p, q) C(r,s) and D(t,u)
<span>
They are congruent if:

</span> $\boxed{(p-m)^2+(q-n)^2=(t-r)^2+(u-s)^2}$ <span>

</span>

4 0

3 years ago

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The price of an Item has been reduced by 80%. The original price was $65. What is the price of the item now?

PIT_PIT [208]

Answer:

$13

Step-by-step explanation:

multiply 65 by 80 then divide by 100, you get 52, so subtract 65 from 52 you get 13

5 0

2 years ago

Cody hiked at an average speed of 1 mile per hour for 5 hours on Saturday. He hiked an average speed of 2 miles per hour for 3 h

ivanzaharov [21]

Answer:

Step 1: Multiply 1x5 Step 2: Multiply 2x3 Step 3: Add the two products

d=v*t

d=distance

v=velocity(speed)

t=time

distance is equal to the product of velocity and time, equation form;

d=vt

Any questions please feel free to ask. Thanks!

3 0

3 years ago

Ghsdgsadhgdhasdhbhdsdhb

kolbaska11 [484]

Cgagcadhfhfjooguo! duolujto

7 0

3 years ago

Zappos is an online retailer based in Nevada and employs 1,300 employees. One of their competitors, Amazon, would like to test t

Amanda [17]

Answer:

$t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402$

$df = n-1= 22-1=21$

$t_{\alpha/2}= -2.08$

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

Step-by-step explanation:

Data given

$\bar X=33.9$ represent the sample mean

$s=4.1$ represent the sample standard deviation

$n=22$ sample size

$\mu_o =26$ represent the value that we want to test

$\alpha=0.025$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 36 years old, the system of hypothesis would be:

Null hypothesis: $\mu \geq 36$

Alternative hypothesis: $\mu < 36$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

And replacing we got:

$t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402$

Now we can calculate the critical value but first we need to find the degreed of freedom:

$df = n-1= 22-1=21$

So we need to find a critical value in the t distribution with df =21 who accumulates 0.025 of the area in the left and we got:

$t_{\alpha/2}= -2.08$

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

3 0

3 years ago