Answer:
- 15
Step-by-step explanation:
Since the vertex is at (-3, 6), the equation is given by
y = a(x + 3) + 6
Therefore, option A is the correct answer.
Answer: The average distance the ambulance travels to reach an emergency situation is 6.64 miles.
Step-by-step explanation:
Hi, to answer this question we have to apply the speed formula:
Speed rate = distance / time
Replacing with the values given:
0.83 miles per minute = d / 8 minutes
Solving for d (distance)
0.83 mpm x 8 m =d
d =6.64 miles
The average distance the ambulance travels to reach an emergency situation is 6.64 miles.
Feel free to ask for more if needed or if you did not understand something.
-x-10>14+2x
Add x for both side
-x+x-10>14+2x+x
-10>14+3x
Subtract 14 for both side
-10-14>14+3x-14
-24>3x
Divided 3 for both side
-24/3>3x/3
-8>x
x<-8
Or
-x-10>14-2x
-3x-10>14
-3x>24
x<-8.
Um, we see that there is one step that are missing which is:
-3x>24. Hope it help!
Answer:
1)-
How to solve your question
Your question is
4(4−72)−9(5+2)
4(4y-7y^{2})-9(5y+2)4(4y−7y2)−9(5y+2)
Simplify
1
Rearrange terms
4(4−72)−9(5+2)
4({\color{#c92786}{4y-7y^{2}}})-9(5y+2)4(4y−7y2)−9(5y+2)
4(−72+4)−9(5+2)
4({\color{#c92786}{-7y^{2}+4y}})-9(5y+2)4(−7y2+4y)−9(5y+2)
2
Distribute
4(−72+4)−9(5+2)
{\color{#c92786}{4(-7y^{2}+4y)}}-9(5y+2)4(−7y2+4y)−9(5y+2)
−282+16−9(5+2)
{\color{#c92786}{-28y^{2}+16y}}-9(5y+2)−28y2+16y−9(5y+2)
3
Distribute
−282+16−9(5+2)
-28y^{2}+16y{\color{#c92786}{-9(5y+2)}}−28y2+16y−9(5y+2)
−282+16−45−18
-28y^{2}+16y{\color{#c92786}{-45y-18}}−28y2+16y−45y−18
4
Combine like terms
2)
−17y+17z+24
See steps
Step by Step Solution:

STEP1:Equation at the end of step 1
((24 - 4 • (5y - 6z)) + 3y) - 7z
STEP2:
Final result :
-17y + 17z + 24
−282+16−45−18
-28y^{2}+{\color{#c92786}{16y}}{\color{#c92786}{-45y}}-18−28y2+16y−45y−18
−282−29−18
-28y^{2}{\color{#c92786}{-29y}}-18−28y2−29y−18
Solution
−282−29−18
