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1 year ago

What is the slope of the line?

Mathematics

1 answer:

12345 [234]1 year ago

8 0

You can find the slope using the following formula:

$\begin{gathered} m=\frac{y2-y1}{x2-x1} \\ where\colon \\ (x1,y1)=(0,2) \\ (x2,y2)=(1,0) \\ m=\frac{0-2}{1-0}=\frac{-2}{1}=-2 \end{gathered}$

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Help solving this math

VMariaS [17]

Answer:

(1) 9n = 56

n = 6

(2) 10 + 4y = 38

y = 7

(3) 3x + 8x = 55

x = 5

(4) 6m + 20 = 8

m= -2

(5) 17 - 3a = 23

a = -2

(6) 10x + 4 = 6x + 16

x = 3

(7) 4(x - 2) + x = 17

x = 5

(8) 2(x + 3) + 3x = x + 22

x = 4

(9) D. 10

(10) -2(3x - 2.4) = 3(3x - 2.4)

im not sure about this equation

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-Unknown

3 0

3 years ago

Need help real fast.

ira [324]

Answer:

option 4

Step-by-step explanation:

using the equation stated above

1st term = -6+(1-1=0)*(6)=-6

4th term= -6+(4-1=3)*6=12

10th term= -6+(10-1=9)*6=48

7 0

4 years ago

Write the equation of the circle graphed below

abruzzese [7]

8,2 I it took me a while but yes That’s the answer

8 0

3 years ago

Sandra throws an object straight up into the air with initial velocity of 38 ft per square from platform that is 30 ft above the

expeople1 [14]

Answer:

3 seconds.

Step-by-step explanation:

We have been given that Sandra throws an object straight up into the air with initial velocity of 38 ft per second from platform that is 30 ft above the ground.

To find the time it will take for object to hit the ground, we will use formula:

$h(t)=-16t^2+v_0t+h_0$ , where, $v_0$ represents initial velocity and $h_0$ represents initial height.

Upon substituting our given initial velocity and initial height, we will get:

$h(t)=-16t^2+38t+30$

We know that object will hit the ground, when height will be 0, so we will equate object's height equal to 0 and solve for t as:

$-16t^2+38t+30=0$

Divide by 2:

$-8t^2+19t+15=0$

Upon using quadratic formula, we will get:

$t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-19\pm\sqrt{19^2-4(-8)(15)}}{2(-8)}$

$t=\frac{-19\pm\sqrt{361+480}}{-16}=\frac{-19\pm\sqrt{841}}{-16}$

$t=\frac{-19\pm29}{-16}$

$t=\frac{-19-29}{-16},t=\frac{-19+29}{-16}$

$t=\frac{-48}{-16},t=\frac{10}{-16}$

$t=3,t=-\frac{5}{8}$

Since time cannot be negative, therefore, it will take 3 seconds for object to hit the ground.

7 0

3 years ago

Quizz the multiple word order of "qenl" is...

Kryger [21]

Answer:

What's that ???????????

5 0

3 years ago