For this case we have the following equation:
We must find the value of "x":
We apply cube root on both sides of the equation to eliminate the exponent:
![x = \sqrt [3] {375}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B375%7D)
We can write 375 as 
So:
![x = \sqrt [3] {5 ^ 3 * 3}\\x = 5 \sqrt [3] {3}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B5%20%5E%203%20%2A%203%7D%5C%5Cx%20%3D%205%20%5Csqrt%20%5B3%5D%20%7B3%7D)
Then, the correct options are:
![x = \sqrt [3] {375}\\x = 5 \sqrt [3] {3}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B375%7D%5C%5Cx%20%3D%205%20%5Csqrt%20%5B3%5D%20%7B3%7D)
Answer:
Option A and B
Answer:
length times width times height
Step-by-step explanation:
Answer:
New length is 3 3/20 ft.
Step-by-step explanation:
The total board is 2 5/8 feet long. And since 5/6 of a foot is trimmed off, that means each piece of wood is 5/6 feet.
We can now set up an equation like this ---> 5/6 ⋅ x = 2 5/8
Now we're going to simplify ---> 5/6 ⋅ x = 2 5/8
5/6 ⋅ x = 21/8
(multiply both sides by 6)
5x = 63/4
(divide both sides by 5)
x = 63/20
x= 3.15
So, the new length is 3.15 feet long, or 3 3/20 in mixed fraction.
Answer : option A
To find the range of scores that represents the middle 50 % of the student who took the test , we find inter quartile
Inter quartile range is the middle 50% of the given range of scores.
The difference between the upper quartile and lower quartile is the inter quartile that is middle 50%
From the diagram , we can see that
Upper quartile = 89
lower quartile = 65
So range is 65% to 89%
