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bixtya [17]
3 years ago
5

6r+7=13+7r help me asap

Mathematics
2 answers:
Westkost [7]3 years ago
7 0

6r+7=13+7r

-6r -6r

------------

7=13+1r

flip the equasin to make it easier

13+1r= 7

-13 -13

---------

1r= -6

jenyasd209 [6]3 years ago
3 0

Answer:

r = - 6

Step-by-step explanation:

Given

6r + 7 = 13 + 7r ( collect terms in r on the left and numbers on the right )

Subtract 7r from both sides

- r + 7 = 13 ( subtract 7 from both sides )

- r = 6 ( multiply both sides by - 1 )

r = - 6

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Dont really understand how to do this
bija089 [108]

Answers:

t_{10} = -22 \ \text{ and } S_{10} = -85

========================================================

Explanation:

t_1 = \text{first term} = 5\\t_2 = \text{first term}-3 = t_1 - 3 = 5-3 = 2

Note we subtract 3 off the previous term (t1) to get the next term (t2). Each new successive term is found this way

t_3 = t_2 - 3 = 2-3 = -1\\t_4 = t_3 - 3 = -1-3 = -4

and so on. This process may take a while to reach t_{10}

There's a shortcut. The nth term of any arithmetic sequence is

t_n = t_1+d(n-1)

We plug in t_1 = 5 \text{ and } d = -3 and simplify

t_n = t_1+d(n-1)\\t_n = 5+(-3)(n-1)\\t_n = 5-3n+3\\t_n = -3n+8

Then we can plug in various positive whole numbers for n to find the corresponding t_n value. For example, plug in n = 2

t_n = -3n+8\\t_2 = -3*2+8\\t_2 = -6+8\\t_2 = 2

which matches with the second term we found earlier. And,

tn = -3n+8\\t_{10} = -3*10+8\\t_{10} = -30+8\\t_{10} = \boldsymbol{-22} \ \textbf{ is the tenth term}

---------------------

The notation S_{10} refers to the sum of the first ten terms t_1, t_2, \ldots, t_9, t_{10}

We could use either the long way or the shortcut above to find all t_1 through t_{10}. Then add those values up. Or we can take this shortcut below.

Sn = \text{sum of the first n terms of an arithmetic sequence}\\S_n = (n/2)*(t_1+t_n)\\S_{10} = (10/2)*(t_1+t_{10})\\S_{10} = (10/2)*(5-22)\\S_{10} = 5*(-17)\\\boldsymbol{S_{10} = -85}

The sum of the first ten terms is -85

-----------------------

As a check for S_{10}, here are the first ten terms:

  • t1 = 5
  • t2 = 2
  • t3 = -1
  • t4 = -4
  • t5 = -7
  • t6 = -10
  • t7 = -13
  • t8 = -16
  • t9 = -19
  • t10 = -22

Then adding said terms gets us...

5 + 2 + (-1) + (-4) + (-7) + (-10) + (-13) + (-16) + (-19) + (-22) = -85

This confirms that S_{10} = -85 is correct.

6 0
2 years ago
What is the answer to this <br> 25=-7(x+5)+5x
Aleksandr [31]

Answer:

x = -25

Step-by-step explanation:

25 = -7(x + 5) + 5x

25 = -7x - 25 + 5x

5x - 7x - 25 = 25

5x - 7x - 25 + 25 = 25 + 25

5x - 7x = 50

-2x = 50

-2x/-2 = 50/-2

x = -25

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2 to 60 is 58 -48 is 10 
so you have think what sort of maths skills are used like it could n+58 -48 then square or something ,but check what the differences are between the numbers.
hope it helped.
8 0
4 years ago
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