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expeople1 [14]
2 years ago
12

What is the correct way to read 43.106

Mathematics
2 answers:
Andrei [34K]2 years ago
6 0

Answer:

Forty three AND one hundred six thousandths

Step-by-step explanation:

If there is a comma ( , ) between the two numbers, you are correct.  

If there is a period / dot ( . ) between them, and you need to read the place values, you must read the numbers to the right of the . as decimals.  Those are the "th" numbers.  1 is in the tenths place, 0 in the hundredths place and the 6 in the thousandths place.  

If you are simply reading out the digit names, without assigning their value, you might say "forty three POINT one hundred six"  or "forty three DOT one hundred six" or "forty three DECIMAL one hundred six".

Sonbull [250]2 years ago
4 0

Step-by-step explanation:

Forty three thousand one hundred and six

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Three varieties of coffee long dash— Coffee​ A, Coffee​ B, and Coffee C long dash— are combined and​ roasted, yielding a 51​-lb
asambeis [7]
Let A, B and C be the number of pounds of each brand of coffee.
A+B+C=51 (weight) which is 3A+B=51 because C=2A, B=51-3A
15.99A+13.21B+19.90A=51×12.82=653.82 (cost) I’ve used C=2A
35.89A+13.21B=653.82
Substitute for B:
35.89A+13.21(51-3A)=653.82
35.89A+673.71-39.63A=653.82
3.74A=19.89, A=117/22 pounds, B=771/22 pounds, C=117/11 pounds.
Approximate weights are A: 5.32lb, B: 35.05lb, C: 10.64lb.
8 0
3 years ago
Which graph represents the solution to the given system? y = –2x + 5 and y = 3x – 2
DaniilM [7]
Y = -2x + 5        y =3x - 2
Since both equations are equal to 'y' you can set them equal to each other to solve.
-2x + 5 = 3x - 2             Subtract 3x from both sides
-5x + 5 = -2                  Subtract 5 from both sides
-5x = -7                        Divide -5 on both sides
x = 7/5
Plug 7/5 back in for x and solve for y.
y = -2(7/5) + 5
y = (-14/5) + (25/5)
y = 11/5
(7/5, 11/5) OR (1.4, 2.2)


4 0
3 years ago
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Answer:

y = 2x

the rise is the 2, and the the run is positive 1, because with graphing its always rise/run, and if there isn't anything below it, it is 2x/1



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2 years ago
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6 0
2 years ago
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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?
kondaur [170]

Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Here, x_1=-8, y_1=-6, x_2=-4, y_2=-14

$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)

$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)

$P(x, y) =(-6, -10)

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Here, x_1=-6, y_1=-10, x_2=-8, y_2=-6

r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}

r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}

r=\sqrt{(-2)^{2}+(4)^{2}}

r=\sqrt{20} units

The standard form of the equation of a circle is

(x-a)^{2}+(y-b)^{2}=r^{2}, where (a, b) are center and r is the radius.

Here, center = (–6, –10) and r=\sqrt{20}

(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}

(x+6)^{2}+(y+10)^{2}=20

Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

4 0
3 years ago
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