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3 years ago

Which ordered pair (c, d) is the solution to the given system of linear equations?

Mathematics

1 answer:

ELEN [110]3 years ago

5 0

Answer:

(-1,6)

Step-by-step explanation:

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What is X ? 9(x−1)−8x=−3(x+5).

musickatia [10]

Answer:

x = - 3 / 2 ( in decimal form = - 1.5)

Step-by-step explanation:

9(x - 1) - 8x = -3(x + 5)

left side: 9(x - 1) - 8x

Expand... 9x - 9 - 8x

= (9x - 8x) - 9

= 1x - 9 or x - 9

right side: -3(x + 5)

Expand... -3x - 15

combine :

x - 9 = -3x - 15

Add 9 to both sides to get x alone

x - 9 + 9 = -3x - 15 + 9

x = -3x - 15 + 9

x = -3x - 6

Add 3x to both sides

x + 3x = -3x - 6 + 3x

simplified, 4x = -6

Now divided 4 from both sides

4x / 4 = -6 / 4

simplify, x = -6 / 4

You can reduce the fraction by dividing it by 2

(-6 / 2) / (4 / 2) = -3 / 2

Hope this helps, Let me know if you have any questions !

Have a nice day :)

5 0

2 years ago

A company purchased 400 units for $20 each on January 31. It purchased 520 units for $26 each on February 28. It sold a total of

kvv77 [185]

Answer:

there is $9360 worth of invertory left as of december 31

Step-by-step explanation:

5 0

3 years ago

What is the solution to = 6

Elan Coil [88]

Answer:

Answer: A. x + (4x - 85) = 90

In this case, the two angles are complementary. This means they add up to 90°. Therefore, the equation is x + (4x - 85) = 90.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

First-order linear differential equations

kkurt [141]

Answer:

$(1)\ logy\ =\ -sint\ +\ c$

$(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Step-by-step explanation:

1. Given differential equation is

$\dfrac{dy}{dt}+ycost = 0$

$=>\ \dfrac{dy}{dt}\ =\ -ycost$

$=>\ \dfrac{dy}{y}\ =\ -cost dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}$

$=>\ logy\ =\ -sint\ +\ c$

Hence, the solution of given differential equation can be given by

$logy\ =\ -sint\ +\ c.$

2. Given differential equation,

$\dfrac{dy}{dt}\ -\ 2ty\ =\ t$

$=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty$

$=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})$

$=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}$

$=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c$

$=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Hence, the solution of given differential equation is

$log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

8 0

4 years ago

A city grid of Anytown, USA is shown on the grid below. The fire department is represented by quadrilateral RSTU. Another fire d

Pavlova-9 [17]

Since the starting and original place is a 4 x 3 rectangle, and the new position already has a side length of 3. We are now going to look for the two points that make a second side of 4. So, the points C(1, -5) and D(4, -5) satisfy the requirements.

7 0

3 years ago

Read 2 more answers