Answer:
A: 500 square feet
Step-by-step explanation:
A: First you have to draw a grid.
You plot the points A,B, and C.
The fourth point would be -5,25 because it matches with the points.
You make a rectangle out of those points
Points AB is 2 feet. Since the interval I used was 5 I would multiply 2 by 5 to get 10.
Then I would find Points BC which is 10 feet. Again multiply it by 5 to get 50.
50 x 10 is 500.
B: Jenna has to reflect over the y-axis. This is because the y-axis is between Quadrants II and I. When reflecting over the y-axis the y-coordinate stays the same but the x-coordinate switches to it's opposite. Basically the x-coordinate is negative in Quadrant II, but in when reflecting over the y-axis the x-coordinate would change to a positive in Quadrant I. So if the point in Quadrant II looks like this: (-X,Y) then when reflecting over the y-axis to Quadrant I would look like this: (X,Y).
Answer:
7.4r+0.3s+12q
Step-by-step explanation:
I am in 8th grade and we do these problems for honors algebra and if you add (8.5q+1.6r)+(3.5q-4.1s)+(4.4s+5.8r) you will get the answer above
A 7/4 because the slope of the line is 7/4
Is it 2 different questions or just one?
For a 30-60-90 triangle
if the shorter leg (oposite 30 degrees) is x then the other leg is x√3 and the hyptonuse is 2x
so
hyptonuse=8
8=2x
4=x
longer leg is 4√3, yep
so shorter leg or height will be 4 units
