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Ira Lisetskai [31]
3 years ago
6

In ΔEFG, is it possible for segment GE to measure 4 units?

Mathematics
2 answers:
Sphinxa [80]3 years ago
7 0

Answer:

Substitution

Step-by-step explanation:

We essentially have x = 180 and a+b+c = x.

So we are just substituting x for a+b+c

polet [3.4K]3 years ago
7 0

Answer:

other person rightt

Step-by-step explanation:

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Prove how they are congruent. Geometry:SSS
Andrej [43]

The <em>additional information</em> needed to prove that both triangles are congruent by the SSS Congruence Theorem would be: <em>C. HJ ≅ LN</em>

<em>Recall:</em>

  • Based on the Side-Side-Side Congruence Theorem, (SSS), two triangles can be said to be congruent to each other if they have three pairs of congruent sides.

Thus, in the two triangles given, the two triangles has:

  • Two pairs of congruent sides - HI ≅ ML and IJ ≅ MN

Therefore, an <em>additional information</em> needed to prove that both triangles are congruent by the SSS Congruence Theorem would be: <em>C. HJ ≅ LN</em>

<em />

Learn more about SSS Congruence Theorem on:

brainly.com/question/4280133

5 0
3 years ago
Read 2 more answers
Suppose the probability that a softball player gets a hit in any single at-bat is 0.300. Assuming that her chance of getting a h
Ksivusya [100]

Answer:

P(X=4)=(1-0.3)^{4-1} 0.3 = 0.103

The probability that she will not get a hit until her fourth time at bat in a game is 0.103

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

P(X=x)=(1-p)^{x-1} p

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

X\sim Geo (1-p)

Solution to the problem

For this case we want this probability

P(X=4)

And using the probability mass function we got:

P(X=4)=(1-0.3)^{4-1} 0.3 = 0.103

The probability that she will not get a hit until her fourth time at bat in a game is 0.103

4 0
3 years ago
Mark all of the statements that are true.
aksik [14]
C.,E
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4 0
3 years ago
The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.
MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle =3\times\ side

3\times\ side =[tex]81\sqrt{3}

Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm

Thus from the diagram , Side AB=BC=AC= 27\sqrt{3} \ cm

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus \angle OBC = 30°

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2}  } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\

Thus ,apothem  OE= 13.5 cm

Now for radius,

We consider ΔOBE

cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB}  \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0
3 years ago
Please answer this, 25 points and will give brainliest!!!
Gekata [30.6K]

Answer:

b

Step-by-step explanation:

The median of a triangle is a line that from the vertex touches the middle lets eliminate options

a=ab starts at a vertex but doensn't touch a the middle of a line X

b=cd starts at a vertex and touches the middle of a line Ye

C= ce stars at a vertex but doesn't end at the middle of a line X

d=mb starts in the middle of the triangle and and ends a vertex X

<u>SO THE CORRECT ANSWER IS B</u>

<em>-hope this helps :)</em>

8 0
3 years ago
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