First problem:
The answer is C because theoretically it should have a 50% of landing
heads but instead it lands heads 56% of the time. Thus this is 6% higher
than 50%. It's not D because there is not specified detail of how the
person got this data so you can assume that the person did a fair
survey/data collection.
Second problem:
So in a data size of 490, 140 of them we trout. This means that 140/490 or 28.57% of the fish are trout. This means that in a sample size of 5000 fish, 5000*0.2857 or 1428.57 are trout.
Third problem:
The Science students seem to have a higher average score because the average score of Math students are:
(32+33+34+34+35+37+39+40+40)/9=36
average score of Science students are:
(41+42+43+43+46+46+47+49+49)/9=45.111
Answer:
a. 13; Equation = 2N - 7 = 19
b. 2; 8 - 3N = 2
Step-by-step explanation:
a. 2N - 7 = 19
- 2N - 7 + 7 = 19 + 7
<u>- 2N</u> = <u>26</u> = 13
2 2
b. 8 - 3N = 2
8 - 8 - 3N = 2 - 8
<u>- 3N</u> = <u>-6</u> = 2
-3 -3
Answer:
angle k:75
angle g:15
Step-by-step explanation:
Answer:
The number of favorable outcomes is 5
Step-by-step explanation:
<u><em>The correct question is</em></u>
How many favorable outcomes are expressed in the fraction 5/12
we know that
The probability of an event is the ratio of the size of the event space to the size of the sample space.
The size of the event space is the number of outcomes in the event you are interested in or the number of favorable outcomes
The size of the sample space is the total number of possible outcomes
In this problem we have
![\frac{5}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B12%7D)
therefore
The number of favorable outcomes is 5
The total number of possible outcomes is 12
Answer: See explanation
Step-by-step explanation:
First and foremost, we should know that: 1 kilogram = 1,000,000 milligrams
Therefore, 1.08kg will be converted to milligram and this will be:
= 1.08 × 1,000,000 milligrams
= 1,080,000 milligrams
Since every plant gets 93mg of fertilizer, the number of plants that can be fertilized will be:
= 1,080,000 / 93
= 11612.903
Therefore, 11612 plants can be fertilized.
The fertilizer left over will be:
= 1,080,000 - (11612 × 93)
= 1080000mg - 1079916mg
= 84 mg