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Katarina [22]
3 years ago
12

Which angle pairs are congruent angle pairs? Select all that apply.

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
6 0

All are angle pair relationship, except consecutive exterior.

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CAN YOU READ THIS AMD IF YOU CAN HELP ME!!!!! THIS CRAZY I NEED PROFESSIONAL!!!!!!!!!!!!!
amm1812

Answer:

1.x=-3,-4

2.A

3.-3,-5

4.C

5.A

6.C

7.D

8.C

Step-by-step explanation:

5 0
3 years ago
Find a solution of inequality 2x+y<10
Vitek1552 [10]

Option C:

The solution of inequality 2x + y < 10 is (5, –3).

Solution:

Given inequality is 2x + y < 10.

Lets substitute the given points in the inequality and find the solution.

Option A: (6, –1)

2(6) + (–1) < 10

12 – 1 < 10

11 < 10

This is false because 11 > 10.

Therefore (6, –1) is not the solution of the inequality.

Option B: (1, 10)

2(1) + (10) < 10

2 + 10 < 10

12 < 10

This is false because 12 > 10.

Therefore (1, 10) is not the solution of the inequality.

Option C: (5, –3)

2(5) + (–3) < 10

10 – 3 < 10

7 < 10

This is true.

Therefore (5, –3) is the solution of the inequality.

Option D: (5, 5)

2(5) + (5) < 10

10 + 5 < 10

15 < 10

This is false because 15 > 10.

Therefore (5, 5) is not the solution of the inequality.

Hence Option C is the correct answer.

The solution of inequality 2x + y < 10 is (5, –3).

7 0
3 years ago
The question is in the image
Drupady [299]

Answer:

h(t) = -5*t^2 + 20*t  + 2

Step-by-step explanation:

First, we know that the motion equation of the ball will be quadratic, so we write the equation:

h(t) = a*t^2 + b*t + c

Now we need to work with the data in the table.

h(1) = 17

h(3) = 17

h(1) = h(2) = 17

Then we have a symmetry around:

(3 - 1)/2 + 1 = 2

Remember that the symmetry is around the vertex of the parabola, then we can conclude that the vertex of the parabola is the point:

(2, h(2)) = (2, 22)

Remember that for a quadratic equation:

y = a*x^2 + b*x + c

with a vertex (h, k)

we can rewrite our function as:

y = a*(x - h)^2 + k

So in this case, we can rewrite our function as:

h(t) = a*(t - 2)^2 + 22

To find the value of a, notice the first point in the table:

(0, 2)

then we have:

h(0) = 2 = a*(0 - 2)^2 + 22

         = 2 = a*(-2)^2 + 22

            2 = a*(4) + 22

           2 - 22 = a*(4)

            -20/4 = -5 = a

Then our function is:

h(t) = -5*(t - 2)^2 + 22

Now we just expand it:

h(t) = -5*(t^2 - 4*t + 4) + 22

h(t) = -5*t^2 + 20*t  + 2

The correct option is the first one.

4 0
3 years ago
Use the quadratic formula to write a quadratic equation that has the solutions x=-4 ± 2/6.
yKpoI14uk [10]

Step-by-step explanation:

general formula

x²-(a+b)x+(ab)

where a is alpha

and b is beta

x=-4+2/6 or x=-4-2/6

x=-1/3 or x=-1

a+b=-1/3 + -1 =-4/3

ab= -1/3 x -1 =1/3

quadratic equation

x²-(-4/3)x + 1/3=0

x² + 4/3x + 1/3=0

multiply through by 3

3x² +4x +1=0

3 0
2 years ago
Read 2 more answers
What is the value of x in the equation, 5 (x + 2) + 4x+ = 6x + 1
kozerog [31]

Answer:

-3

Step-by-step explanation:

first distribute 5 to x and 2 =5x+10 then combine like terms to 5x+4x=9x so on one side u have 9x+10 then on the other side of the equation u have 6x+1 now get the whole numbers on one side of the equation and variables on the other.

9x+10=6x+1

-6x -6x

3x+10=1

-10. -10

<u>3x</u>=<u>-9</u>

3. 3

-3=x

6 0
3 years ago
Read 2 more answers
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